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UNIX网络编程练习-大小端判断

2015-11-30 10:59 411 查看
#include <stdlib.h>
#include <stdio.h>
#include <iostream>
#include <string.h>
#include <unistd.h>

using namespace std;
#define CPU_VENDOR_OS "sparc64-unknown-freebsd5.1"

int main(int argc, char* argv[])
{
	union {
		short s;
		char c[sizeof(short)];
	} un;

	un.s = 0x0102;
	printf("%s \n", CPU_VENDOR_OS);

	if(sizeof(short) == 2) {
		if(un.c[0] == 1 && un.c[1] == 2)
			cout<<"big-endian"<<endl;
		else if(un.c[0] == 2 && un.c[1] == 1)
			cout<<"little-endian"<<endl;
		else
			cout<<"unknow"<<endl;
	} else {
		cout<<"sizeof(short) = "<<sizeof(short)<<endl;
	}

	return 1;
}


输出结果:



union 联合, 一种特殊的类, 数据共享同一段内存, 以达到节省空间的目的.

举例:

#include <stdlib.h>
#include <stdio.h>
#include <iostream>
#include <string.h>
#include <unistd.h>

using namespace std;
#define CPU_VENDOR_OS "sparc64-unknown-freebsd5.1"

int main(int argc, char* argv[])
{
    union {
        int i;
        struct {
            char first;
            char second;
        } half;
    } un; 

    un.i = 0x4241;
    cout<<hex<<un.i<<endl;
    cout<<hex<<(int)un.half.first<<"  "<<(int)un.half.second<<endl;

    un.half.first = 'a';
    un.half.second = 'b';
    cout<<hex<<un.i<<endl;

    return 1;
}


输出结果:

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