如何取得android唯一码?
2015-11-23 16:19
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如何取得android唯一码?
问题
每一个android装置都有唯一ID吗?如果有?怎么用java最简单取得呢?回答1(最佳)
如何取得android唯一码?好处:
1.不需要特定权限.
2.在99.5% Android装置(包括root过的)上,即API => 9,保证唯一性.
3.重装app之后仍能取得相同唯一值.
伪代码:
if API => 9/10: (99.5% of devices) return unique ID containing serial id (rooted devices may be different) else return unique ID of build information (may overlap data - API < 9)
代码:
/** * Return pseudo unique ID * @return ID */public static String getUniquePsuedoID() { // If all else fails, if the user does have lower than API 9 (lower // than Gingerbread), has reset their device or 'Secure.ANDROID_ID' // returns 'null', then simply the ID returned will be solely based // off their Android device information. This is where the collisions // can happen. // Thanks http://www.pocketmagic.net/?p=1662! // Try not to use DISPLAY, HOST or ID - these items could change. // If there are collisions, there will be overlapping data String m_szDevIDShort = "35" + (Build.BOARD.length() % 10) + (Build.BRAND.length() % 10) + (Build.CPU_ABI.length() % 10) + (Build.DEVICE.length() % 10) + (Build.MANUFACTURER.length() % 10) + (Build.MODEL.length() % 10) + (Build.PRODUCT.length() % 10); // Thanks to @Roman SL! // http://stackoverflow.com/a/4789483/950427 // Only devices with API >= 9 have android.os.Build.SERIAL // http://developer.android.com/reference/android/os/Build.html#SERIAL // If a user upgrades software or roots their device, there will be a duplicate entry String serial = null; try { serial = android.os.Build.class.getField("SERIAL").get(null).toString(); // Go ahead and return the serial for api => 9 return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString(); } catch (Exception exception) { // String needs to be initialized serial = "serial"; // some value } // Thanks @Joe! // http://stackoverflow.com/a/2853253/950427 // Finally, combine the values we have found by using the UUID class to create a unique identifier return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();}
回答2
好处:1.不需要特定权限.
2.在100% Android装置(包括root过的)上,保证唯一性.
坏处
1.重装app之后不能取得相同唯一值.
private static String uniqueID = null; private static final String PREF_UNIQUE_ID = "PREF_UNIQUE_ID"; public synchronized static String id(Context context) { if (uniqueID == null) { SharedPreferences sharedPrefs = context.getSharedPreferences( PREF_UNIQUE_ID, Context.MODE_PRIVATE); uniqueID = sharedPrefs.getString(PREF_UNIQUE_ID, null); if (uniqueID == null) { uniqueID = UUID.randomUUID().toString(); Editor editor = sharedPrefs.edit(); editor.putString(PREF_UNIQUE_ID, uniqueID); editor.commit(); } } return uniqueID; }
回答3(需要有电话卡)
好处:1.重装app之后仍能取得相同唯一值.
代码:
final TelephonyManager tm = (TelephonyManager) getBaseContext().getSystemService(Context.TELEPHONY_SERVICE); final String tmDevice, tmSerial, androidId; tmDevice = "" + tm.getDeviceId(); tmSerial = "" + tm.getSimSerialNumber(); androidId = "" + android.provider.Settings.Secure.getString(getContentResolver(), android.provider.Settings.Secure.ANDROID_ID); UUID deviceUuid = new UUID(androidId.hashCode(), ((long)tmDevice.hashCode() << 32) | tmSerial.hashCode()); String deviceId = deviceUuid.toString();
谨记:要取得以下权限
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
stackoverflow链接:
http://stackoverflow.com/questions/2785485/is-there-a-unique-android-device-id
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