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MySQL不支持动态表名

2015-11-23 15:47 585 查看
今天写一个数据迁移的存储过程,用到了动态表名,发现MYSQL不支持直接使用变量做表名。然后就用下面的方式来做了。

DROP PROCEDURE IF EXISTS p_transfer_data;
delimiter //

CREATE PROCEDURE p_transfer_data()
begin
declare v_dbname varchar(100) default database();
declare v_tabname varchar(100);
declare flag int default 0;  /*是否达到记录的末尾控制变量*/

DECLARE v_cur CURSOR FOR SELECT table_name FROM  information_schema.TABLES WHERE  TABLE_SCHEMA=v_dbname AND table_name like 't_2%' order by table_name desc;

DECLARE CONTINUE HANDLER FOR NOT FOUND SET flag = 1;
open v_cur;
FETCH v_cur INTO v_tabname;/*获取第一条记录*/

while flag <> 1 do
set @preparable_stmt1=CONCAT("insert into t_x(ID_,NAME)  select ID_,NAME ",v_tabname);
set @preparable_stmt2=CONCAT("insert into t_y(ID_,AREA) select ID_,AREA from ",v_tabname);
prepare preparable_stmt1 from @preparable_stmt1;
prepare preparable_stmt2 from @preparable_stmt2;
EXECUTE preparable_stmt1;
EXECUTE preparable_stmt2;
FETCH v_cur INTO v_tabname;/*取下一条记录*/
end while;
close v_cur;

end;
//

delimiter ;

-- call p_transfer_data();
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