Android如何获取asset下的xml文件，并解析

1.asset下的自定义xml文件:

<Language cat="it">
<lan id="1">
<name>Java</name>
<ide>Eclipse</ide>
</lan>
<lan id="2">
<name>Swift</name>
<ide>Xcode</ide>
</lan>
<lan id="3">
<name>C#</name>
<ide>Visual Studio</ide>
</lan>
</Language>

2.activity解析代码:

</pre><pre name="code" class="java">import java.io.IOException;
import java.io.InputStream;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
import android.app.Activity;
import android.os.Bundle;
import android.widget.TextView;

public class MainActivity extends Activity {

private TextView tv_show;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
tv_show = (TextView) findViewById(R.id.tv_show);

try {
//传入文件名：language.xml；用来获取流
InputStream is = getAssets().open("language.xml");
//首先创造：DocumentBuilderFactory对象
DocumentBuilderFactory dBuilderFactory = DocumentBuilderFactory.newInstance();
//获取：DocumentBuilder对象
DocumentBuilder dBuilder = dBuilderFactory.newDocumentBuilder();
//将数据源转换成：document 对象
Document document = dBuilder.parse(is);
//获取根元素
Element element = (Element) document.getDocumentElement();
//获取子对象的数值 读取lan标签的内容
NodeList nodeList = element.getElementsByTagName("lan");
for (int i = 0; i < nodeList.getLength(); i++) {
//获取对应的对象
Element lan = (Element) nodeList.item(i);
//lan.getAttribute("id") 获取id的值
tv_show.append(lan.getAttribute("id")+"\n");
//获取name标签下的内容
tv_show.append(lan.getElementsByTagName("name").item(0).getTextContent()+"\n");
//获取ide标签下的内容
tv_show.append(lan.getElementsByTagName("ide").item(0).getTextContent()+"\n");
}

} catch (IOException e) {
e.printStackTrace();
} catch (ParserConfigurationException e) {
e.printStackTrace();
} catch (SAXException e) {
e.printStackTrace();
}
}
}