第三次作业

1. 设计一个类（不妨叫做A ），实现对一维数组(a[100])的指定范围内的元素相加运算。

1 package sijue;
2 import java.util.Scanner;//用于从键盘导入数据
3
4 public class A {
5     public static void main(String[]args){
6         int[] list={-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767};
7         int sum=0;//存放和
8         Scanner a= new Scanner(System.in) ;//Scanner类的对象a用来接收来自键盘的数据
9         System.out.println("请输入起点：");
10         int x=a.nextInt();
11         System.out.println("请输入终点：");
12         int y=a.nextInt();
13         System.out.println("从"+x+"到"+y+"的和为");
14         for(int i=x;i<=y;i++)
15         sum+=list[i]; //循环
16         System.out.println(sum);
17               }
18          }

运行结果：



2. 设计一个类（不妨叫做B ），实现对二维数组(a
[M])的指定范围内的元素相加运算。

1 package sijue;
2 import java.util.Scanner;
3 public class B {
4      public static void main(String[]args){
5             int[][] a={{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767},{2740,-4182,-5632,-2966,-1953,567,-8570,1046,2211,1572,-2503,-1899,3183,-6187,3330,3492,-464,-2104,316,8136,470,50,466,-1424,5809,2131,6418,-3018,6002,-8379,1433,1144,2124,1624,-602,-5518,5872,870,-5175,-3961,-427,-6284,2850,481,6175,141,-766,-1897,-748,-4248,366,4823,3003,1778,3256,2182,2253,5076,5540,-2650,2451,-1875,5482,-6881,-329,-969,-8032,-2093,612,1524,-5492,5758,-7401,-5039,3241,6338,3581,4321,-1072,4942,2131,210,-7045,-7514,7450,-1142,-2666,-4485,-639,2121,-5298,-3805,-1686,-2520,-1680,2321,-4617,-1961,2076,7309}};
6             int sum=0;
7             Scanner b = new Scanner(System.in);
8             System.out.println("起始行：");
9             int x1 = b.nextInt();
10             System.out.println("终点行");//x取值为1-2
11             int y1 =b.nextInt();
12             System.out.println("起始列：");
13             int x2 = b.nextInt();
14             System.out.println("终点列：");//y取值为1-100
15             int y2 =b.nextInt();
16             System.out.println("从("+x1+","+x2+")到"+"("+y1+","+y2+")的和为");
17             for(int i=x1-1;i<=y1-1;i++)
18             {
19                 for(int j=x2-1;j<=y2-1;j++)
20                 {
21                 sum+=a[i][j];
22                 }
23             }
24             System.out.println(sum);
25         }
26     }

运行结果：



3. 设计一个类（不妨叫做C ），实现对三维数组的指定范围内的元素相加运算。

1 package sijue;
2 import java.util.Scanner;
3 public class C {
4     public static void main(String[]args){
5         int sum=0;
6         int[][][] a= new int[][][]
7            {
8               {{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767}},
9               {{2740,-4182,-5632,-2966,-1953,567,-8570,1046,2211,1572,-2503,-1899,3183,-6187,3330,3492,-464,-2104,316,8136,470,50,466,-1424,5809,2131,6418,-3018,6002,-8379,1433,1144,2124,1624,-602,-5518,5872,870,-5175,-3961,-427,-6284,2850,481,6175,141,-766,-1897,-748,-4248,366,4823,3003,1778,3256,2182,2253,5076,5540,-2650,2451,-1875,5482,-6881,-329,-969,-8032,-2093,612,1524,-5492,5758,-7401,-5039,3241,6338,3581,4321,-1072,4942,2131,210,-7045,-7514,7450,-1142,-2666,-4485,-639,2121,-5298,-3805,-1686,-2520,-1680,2321,-4617,-1961,2076,7309}},
10               {{302,-7944,-6551,6648,-884,-6332,1188,-248,3902,-2171,-3782,-3510,6203,-636,-4605,4497,3187,-6278,1198,-7963,7647,-3022,-8267,7995,-1998,-4171,730,-8117,-1706,7601,-2454,-6161,-1810,243,-2841,-5377,2985,2328,177,5622,3596,3057,2830,-1151,6566,2254,6972,-3060,4063,367,84,3156,3880,-1530,5272,1385,-565,-1736,1267,-3863,-229,2072,2423,-7449,9555,2844,-1278,-3613,-919,4153,-4232,4032,-5732,199,4792,2498,-3344,-4193,2650,-579,3416,-3575,1822,-6936,-2661,-1873,414,2314,6844,7613,-7844,6680,5974,2208,-3597,6302,4396,-141,-1864,1939}}
11              };
12         Scanner c= new Scanner(System.in) ;
13         System.out.println("x轴起点：");
14         int x1 = c.nextInt() ;
15         System.out.println("x轴终点：");//x取值为1-3
16         int x2 =c.nextInt();
17         System.out.println("y轴起点：");
18         int y1 = c.nextInt() ;
19         System.out.println("y轴终点：");//y取值为1
20         int y2 =c.nextInt();
21         System.out.println("z轴起点：");
22         int z1 = c.nextInt() ;
23         System.out.println("z轴终点：");//z取值为1-100
24         int z2 =c.nextInt();
25         System.out.println("从("+x1+","+y1+","+z1+")到"+"("+x2+","+y2+","+z2+")的和为:");
26         for(int i=x1-1;i<=x2-1;i++)
27         {
28             for(int j=y1-1;j<=y2-1;j++)
29             {
30                 for(int m=z1-1;m<=z2-1;m++)
31                 {
32                 sum+=a[i][j][m];
33                 }
34             }
35         }
36         System.out.println(sum);
37    }
38 }

运行结果：


小结：

这次的作业完成的极其不顺利，在一开始老师布置作业的时候，我就有点懵，完全不懂老师让做什么，再加上本身变成并不拿手，这个作业也搁浅了相当久，但是在看到老师和助教在QQ群里的讲解后就恍然大悟了，也借鉴了同学的思想，比如说Scanner类的nextInt方法可从键盘导入数据，这个用法在学习Java的时候遇到过，然而我并没有记住并实践。