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身份证 取性别,年龄,出生日期

2015-11-17 15:51 726 查看
with T as ( SELECT [idCard], (right(left([idCard],10),4)+'-'+right(left([idCard],12),2)+'-'+right(left([idCard],14),2)) 'Birthday', (case when (left(right([idCard],2),1) % 2 = 0) then '女' else '男' end ) Sex FROM [TestIDCard] where len([idCard])=18 union all SELECT [idCard], ('19'+right(left([idCard],8),2)+'-'+right(left([idCard],10),2)+'-'+right(left([idCard],12),2)) 'Birthday', (case when (right([idCard],1) % 2 = 0) then '女' else '男' end ) Sex FROM [TestIDCard] where len([idCard])=15 ) select *,(year(getdate())-(cast(left(T.Birthday,4) as int))) 'AGE' from T
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