Remove Element<leetcode>

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.
删除数组中和elem相等的元素，并且返回新数组大小。

class Solution {

public:

int removeElement(vector<int>& nums, int val) {

//vector<int>::iterator it = nums.begin();

int i=0,start=0;

//for(; it != nums.end(); it++)

//for(; i < nums.size(); i++ )

int length = nums.size();

while(i < length)

{

if(nums[i] != val)

{

//nums.erase(&nums[i]);

nums[start] = nums[i];

start++;

i++;

}

else

i++;



}

return start;

}

};