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1031. Hello World for U (20)

2015-11-14 20:41 267 查看
1.通过 n1 =
n3 =
max { k| k <= n2 for
all 3 <= n2 <=
N } with n1 +
n2 +
n3 -
2 = N的条件,通过for循环求出最大的n1

//#include<string>
//#include <iomanip>
#include<vector>
#include <algorithm>
//#include<stack>
#include<set>
#include<queue>
#include<map>
//#include<unordered_set>
//#include<unordered_map>
//#include <sstream>
//#include "func.h"
//#include <list>
#include<stdio.h>
#include<iostream>
#include<string>
#include<memory.h>
#include<limits.h>
using namespace std;

int main(void)
{
string s;
cin >> s;
int n = s.size();
int n1 = 0, n2 = 0;
for (int i = 0; i < n; i++)
{//求出n1的最大值
n1 = i;
n2 = n + 2 - 2 * n1;
if (n2 < n1) break;
}
if (n2 < n1)
n1--;
n2 = n + 2 - 2 * n1;
string mid = "";
for (int i = 0; i < n2 - 2; i++)
mid += " ";

for (int i = 0; i < n1 - 1; i++)
{
cout << s[i] << mid << s[s.size() - 1 - i] << endl;
}
for (int i = n1 - 1; i < n1 - 1 + n2; i++)
{
cout << s[i];
}
cout << endl;
return 0;
}
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