您的位置:首页 > Web前端 > JavaScript

一个简单json数据提交实例

2015-11-07 14:28 639 查看
1.客户端编程:jsp页面
<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<script type="text/javascript" src="js/jquery-1.4.2.js"></script>
<script type="text/javascript" src="js/json2.js"></script>
<body>
<form action="">
<table>
<tr>
<td>名字</td>
<td><input type="text" id="name" name="name"/></td>
</tr>
<tr>
<td>年龄</td>
<td><input type="text" id="age" name="age"/></td>
</tr>
<tr>
<td><input type="button" value="提交" onclick="commit();"/> </td>
</tr>
</table>
<table id="ulist" border="2">
</table>
</form>
</body>
<script type="text/javascript">
function commit(){
    $.ajax(
            {type
: "post",
             data:{name:$('#name').val(),age:$('#age').val()},
             url
: "testJson_testJson.action",
             dataType
: "JSON",
             success
: callback
                }
            );
}
function callback(data){
    var
json =  JSON.parse(data);
    alert("fdf");
    var
ulist =  $("#ulist");
    $.each(json,
function(i,item){
         ulist.append(
        "<tr><td>"+item.name+"</td><td>"+item.age+"</td></tr>"
                 );
        })
}
</script>
</html>
2.服务端编程:用到sturst2

public class Person {
    private
String name;
    private
String age;
    public
String getName() {
        return
name;
    }
    public
void setName(String name) {
        this.name
= name;
    }
    public
String getAge() {
        return
age;
    }
    public
void setAge(String age) {
        this.age
= age;
    }

}

public class TestJsonAction {

    private
static final long serialVersionUID = -3571998877536556903L;

    public
String testJson() throws Exception {
        Person
p1 = new Person();
        p1.setName("nn");
        p1.setAge("11");
        Person
p2 = new Person();
        p2.setName("gg");
        p2.setAge("12");
        Person
p3 = new Person();
        p3.setName("rr");
        p3.setAge("24");
        List<Person>
ulist = new ArrayList<Person>();
        ulist.add(p1);
      
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: