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2015-11-02 15:57 274 查看
15.9. order by子句
查询返回的列表(list)可以按照一个返回的类或组件(components)中的任何属性(property)进行排序:
代码内容
from DomesticCat cat
order by cat.name asc, cat.weight desc, cat.birthdate

可选的asc或desc关键字指明了按照升序或降序进行排序.

15.10. group by子句
一个返回聚集值(aggregate values)的查询可以按照一个返回的类或组件(components)中的任何属性(property)进行分组:
代码内容
select cat.color, sum(cat.weight), count(cat)
from Cat cat
group by cat.color
select foo.id, avg(name), max(name)
from Foo foo join foo.names name
group by foo.id
having子句在这里也允许使用.
select cat.color, sum(cat.weight), count(cat)
from Cat cat
group by cat.color
having cat.color in (eg.Color.TABBY, eg.Color.BLACK)

如果底层的数据库支持的话(例如不能在MySQL中使用),SQL的一般函数与聚集函数也可以出现 在having与order by 子句中。
代码内容
select cat
from Cat cat
join cat.kittens kitten
group by cat
having avg(kitten.weight) > 100
order by count(kitten) asc, sum(kitten.weight) desc

注意group by子句与 order by子句中都不能包含算术表达式(arithmetic expressions).
15.11. 子查询
对于支持子查询的数据库,Hibernate支持在查询中使用子查询。一个子查询必须被圆括号包围起来(经常是SQL聚集函数的圆括号)。 甚至相互关联的子查询(引用到外部查询中的别名的子查询)也是允许的。
代码内容
from Cat as fatcat
where fatcat.weight > (
select avg(cat.weight) from DomesticCat cat
)
from DomesticCat as cat
where cat.name = some (
select name.nickName from Name as name
)
from Cat as cat
where not exists (
from Cat as mate where mate.mate = cat
)
from DomesticCat as cat
where cat.name not in (
select name.nickName from Name as name
)

在select列表中包含一个表达式以上的子查询,你可以使用一个元组构造符(tuple constructors):
代码内容
from Cat as cat
where not ( cat.name, cat.color ) in (
select cat.name, cat.color from DomesticCat cat
)

注意在某些数据库中(不包括Oracle与HSQL),你也可以在其他语境中使用元组构造符, 比如查询用户类型的组件与组合:
代码内容
from Person where name = (’Gavin’, ’A’, ’King’)

该查询等价于更复杂的:
代码内容
from Person where name.first = ’Gavin’ and name.initial = ’A’ and name.last = ’King’)

有两个很好的理由使你不应当作这样的事情:首先,它不完全适用于各个数据库平台;其次,查询现在依赖于映射文件中属性的顺序。
15.12. HQL示例
Hibernate查询可以非常的强大与复杂。实际上,Hibernate的一个主要卖点就是查询语句的威力。这里有一些例子,它们与我在最近的 一个项目中使用的查询非常相似。注意你能用到的大多数查询比这些要简单的多!
下面的查询对于某个特定的客户的所有未支付的账单,在给定给最小总价值的情况下,返回订单的id,条目的数量和总价值, 返回值按照总价值的结果进行排序。为了决定价格,查询使用了当前目录。作为转换结果的SQL查询,使用了ORDER, ORDER_LINE, PRODUCT, CATALOG 和PRICE 库表。
代码内容
select order.id, sum(price.amount), count(item)
from Order as order
join order.lineItems as item
join item.product as product,
Catalog as catalog
join catalog.prices as price
where order.paid = false
and order.customer = :customer
and price.product = product
and catalog.effectiveDate < sysdate
and catalog.effectiveDate >= all (
select cat.effectiveDate
from Catalog as cat
where cat.effectiveDate < sysdate
)
group by order
having sum(price.amount) > :minAmount
order by sum(price.amount) desc

这简直是一个怪物!实际上,在现实生活中,我并不热衷于子查询,所以我的查询语句看起来更像这个:
代码内容
select order.id, sum(price.amount), count(item)
from Order as order
join order.lineItems as item
join item.product as product,
Catalog as catalog
join catalog.prices as price
where order.paid = false
and order.customer = :customer
and price.product = product
and catalog = :currentCatalog
group by order
having sum(price.amount) > :minAmount
order by sum(price.amount) desc

下面一个查询计算每一种状态下的支付的数目,除去所有处于AWAITING_APPROVAL状态的支付,因为在该状态下 当前的用户作出了状态的最新改变。该查询被转换成含有两个内连接以及一个相关联的子选择的SQL查询,该查询使用了表 PAYMENT, PAYMENT_STATUS 以及 PAYMENT_STATUS_CHANGE。
代码内容
select count(payment), status.name
from Payment as payment
join payment.currentStatus as status
join payment.statusChanges as statusChange
where payment.status.name <> PaymentStatus.AWAITING_APPROVAL
or (
statusChange.timeStamp = (
select max(change.timeStamp)
from PaymentStatusChange change
where change.payment = payment
)
and statusChange.user <> :currentUser
)
group by status.name, status.sortOrder
order by status.sortOrder

如果我把statusChanges实例集映射为一个列表(list)而不是一个集合(set), 书写查询语句将更加简单.
代码内容
select count(payment), status.name
from Payment as payment
join payment.currentStatus as status
where payment.status.name <> PaymentStatus.AWAITING_APPROVAL
or payment.statusChanges[ maxIndex(payment.statusChanges) ].user <> :currentUser
group by status.name, status.sortOrder
order by status.sortOrder

下面一个查询使用了MS SQL Server的 isNull()函数用以返回当前用户所属组织的组织帐号及组织未支付的账。 它被转换成一个对表ACCOUNT, PAYMENT, PAYMENT_STATUS, ACCOUNT_TYPE, ORGANIZATION 以及 ORG_USER进行的三个内连接, 一个外连接和一个子选择的SQL查询。
代码内容
select account, payment
from Account as account
left outer join account.payments as payment
where :currentUser in elements(account.holder.users)
and PaymentStatus.UNPAID = isNull(payment.currentStatus.name, PaymentStatus.UNPAID)
order by account.type.sortOrder, account.accountNumber, payment.dueDate

对于一些数据库,我们需要弃用(相关的)子选择。
代码内容
select account, payment
from Account as account
join account.holder.users as user
left outer join account.payments as payment
where :currentUser = user
and PaymentStatus.UNPAID = isNull(payment.currentStatus.name, PaymentStatus.UNPAID)
order by account.type.sortOrder, account.accountNumber, payment.dueDate

15.13. 批量的UPDATE & DELETE语句
HQL现在支持UPDATE与DELETE语句. 查阅 第 14.3 节 “大批量更新/删除(Bulk update/delete)” 以获得更多信息。
15.14. 小技巧 & 小窍门
你可以统计查询结果的数目而不必实际的返回他们:
( (Integer) session.iterate("select count(*) from ....").next() ).intValue()
若想根据一个集合的大小来进行排序,可以使用如下的语句:
代码内容
select usr.id, usr.name
from User as usr
left join usr.messages as msg
group by usr.id, usr.name
order by count(msg)

如果你的数据库支持子选择,你可以在你的查询的where子句中为选择的大小(selection size)指定一个条件:
代码内容
from User usr where size(usr.messages) >= 1

如果你的数据库不支持子选择语句,使用下面的查询:
代码内容
select usr.id, usr.name
from User usr.name
join usr.messages msg
group by usr.id, usr.name
having count(msg) >= 1

因为内连接(inner join)的原因,这个解决方案不能返回含有零个信息的User 类的实例, 所以这种情况下使用下面的格式将是有帮助的:
代码内容
select usr.id, usr.name
from User as usr
left join usr.messages as msg
group by usr.id, usr.name
having count(msg) = 0

JavaBean的属性可以被绑定到一个命名查询(named query)的参数上:
代码内容
Query q = s.createQuery("from foo Foo as foo where foo.name=:name and foo.size=:size");
q.setProperties(fooBean); // fooBean包含方法getName()与getSize()
List foos = q.list();

通过将接口Query与一个过滤器(filter)一起使用,集合(Collections)是可以分页的:
代码内容
Query q = s.createFilter( collection, "" ); // 一个简单的过滤器
q.setMaxResults(PAGE_SIZE);
q.setFirstResult(PAGE_SIZE * pageNumber);
List page = q.list();

通过使用查询过滤器(query filter)可以将集合(Collection)的原素分组或排序:
代码内容
Collection orderedCollection = s.filter( collection, "order by this.amount" );
Collection counts = s.filter( collection, "select this.type, count(this) group by this.type" );

不用通过初始化,你就可以知道一个集合(Collection)的大小:
代码内容
( (Integer) session.iterate("select count(*) from ....").next() ).intValue();
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