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programming-challenges Bee Maja (111204) 题解

2015-10-30 01:59 309 查看
本题可以通过找规律解决,事实上每个格子的值可以通过相邻的两个格子算出来的。我画了一个大大的图,其实也花了不少时间。

#include <iostream>
#include <sstream>
#include <fstream>
#include <string>
#include <vector>
#include <list>
#include <queue>
#include <map>
#include <set>
#include <stack>
#include <assert.h>
#include <algorithm>
#include <math.h>
#include <ctime>
#include <functional>
#include <string.h>
#include <stdio.h>
#include <numeric>
#include <float.h>

using namespace std;

const int MAXNUM = 100000;

struct Node {
int i1, i2;
Node() : i1(0), i2(0) {}
Node(int ai1, int ai2) : i1(ai1), i2(ai2) {}
};

Node addNode(const Node &n1, const Node &n2, int level) {
Node newNode;
if (n1.i1 == level && n2.i1 == level) {
newNode.i1 = level + 1;
}
else if (n1.i1 == -level && n2.i1 == -level) {
newNode.i1 = -level - 1;
}
else if (n1.i1 > 0 || n2.i1 > 0) {
newNode.i1 = max(n1.i1, n2.i1);
}
else {
newNode.i1 = min(n1.i1, n2.i1);
}

if (n1.i2 == level && n2.i2 == level) {
newNode.i2 = level + 1;
}
else if (n1.i2 == -level && n2.i2 == -level) {
newNode.i2 = -level - 1;
}
else if (n1.i2 > 0 || n2.i2 > 0) {
newNode.i2 = max(n1.i2, n2.i2);
}
else {
newNode.i2 = min(n1.i2, n2.i2);
}

return newNode;
}

vector<Node> vNodes;

int main() {
vNodes.push_back(Node(0, 0));
vNodes.push_back(Node(0, 1));
vNodes.push_back(Node(-1, 1));
vNodes.push_back(Node(-1, 0));
vNodes.push_back(Node(0, -1));
vNodes.push_back(Node(1, -1));
vNodes.push_back(Node(1, 0));

int minorLoop = 0;
int lastMinorLoop = 0;
while (vNodes.size() <= MAXNUM) {
lastMinorLoop++;
minorLoop = lastMinorLoop * 6;

int startIndex = vNodes.size() - minorLoop;

for (int i = 1; i <= minorLoop; i++) {
int delta = i - 1;
if (i == 1) {
vNodes.push_back(addNode(vNodes[startIndex], vNodes.back(), lastMinorLoop));
}
else {
vNodes.push_back(addNode(vNodes[startIndex + delta], vNodes[startIndex + delta - 1], lastMinorLoop));
}

if ((i) % lastMinorLoop == 0) {
vNodes.push_back(addNode(vNodes[startIndex + delta],  vNodes[startIndex + delta], lastMinorLoop));
}

if (vNodes.size() > MAXNUM) break;
}
}

int nodeId = 0;

while (cin >> nodeId) {
cout << vNodes[nodeId - 1].i1 << " " << vNodes[nodeId - 1].i2 << endl;
}

return 0;
}
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