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lua State加载部分库

2015-10-28 18:03 423 查看
在lua中，通常我们用luaL_openlibs(L)加载所有的lub标准库，但是有时候我们想只加载部分，有没有什么好的办法呢？在luaproc看到如下办法：

static void registerlib( lua_State *L, const char *name, lua_CFunction f ) {
lua_getglobal( L, "package" );
lua_getfield( L, -1, "preload" );
lua_pushcfunction( L, f );
lua_setfield( L, -2, name );
lua_pop( L, 2 );
}

static void openlibs( lua_State *L ) {
lua_cpcall( L, luaopen_base, NULL );
lua_cpcall( L, luaopen_package, NULL );
registerlib( L, "io", luaopen_io );
registerlib( L, "os", luaopen_os );
registerlib( L, "table", luaopen_table );
registerlib( L, "string", luaopen_string );
registerlib( L, "math", luaopen_math );
registerlib( L, "debug", luaopen_debug );
}


int lua_cpcall (lua_State *L, lua_CFunction func, void *ud);

Calls the C function 
func
in protected mode. 
func
starts with only one element in its stack, a light userdata containing 
ud
. In case of errors, 
lua_cpcall
 returns the same error codes as 
lua_pcall
, plus the error object on the top of the stack; otherwise, it returns zero, and does not change the stack. All values returned by 
func
are discarded.

上面是5.1的做法。luaproc新做法如下：

static void luaproc_reglualib( lua_State *L, const char *name,
lua_CFunction f ) {
lua_getglobal( L, "package" );
lua_getfield( L, -1, "preload" );
lua_pushcfunction( L, f );
lua_setfield( L, -2, name );
lua_pop( L, 2 );
}

static void luaproc_openlualibs( lua_State *L ) {
requiref( L, "_G", luaopen_base, FALSE );
requiref( L, "package", luaopen_package, TRUE );
luaproc_reglualib( L, "io", luaopen_io );
luaproc_reglualib( L, "os", luaopen_os );
luaproc_reglualib( L, "table", luaopen_table );
luaproc_reglualib( L, "string", luaopen_string );
luaproc_reglualib( L, "math", luaopen_math );
luaproc_reglualib( L, "debug", luaopen_debug );
#if (LUA_VERSION_NUM == 502)
luaproc_reglualib( L, "bit32", luaopen_bit32 );
#endif
#if (LUA_VERSION_NUM >= 502)
luaproc_reglualib( L, "coroutine", luaopen_coroutine );
#endif
#if (LUA_VERSION_NUM >= 503)
luaproc_reglualib( L, "utf8", luaopen_utf8 );
#endif

}
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