opencv3寻找最小包围矩形-minAreaRect函数

#include<iostream>
#include<vector>
#include<opencv2/opencv.hpp>

using namespace cv;
using namespace std;

int main()
{
Mat srcImage(Size(600, 600), CV_8UC3, Scalar(0));

RNG &rng = theRNG();

char key;
while (1)
{
//随机生成一些点
//首先就是随机生成点的总数量
int g_nPointCount = rng.uniform(3, 200);
//接下来就是随机生成一些点的坐标
vector<Point> points;
for (int i = 0; i < g_nPointCount; i++)
{
Point midPoint;

midPoint.x = rng.uniform(srcImage.cols / 4, srcImage.cols * 3 / 4);
midPoint.y = rng.uniform(srcImage.rows / 4, srcImage.rows * 3 / 4);

points.push_back(midPoint);
}

//显示刚刚随机生成的那些点
for (int i = 0; i < g_nPointCount; i++)
{
circle(srcImage, points[i], 0, Scalar(rng.uniform(0, 255), rng.uniform(0, 255), rng.uniform(0, 255)), 3);
}

//在生成的那些随机点中寻找最小包围矩形
//rectPoint变量中得到了矩形的四个顶点坐标
RotatedRect rectPoint = minAreaRect(points);
//定义一个存储以上四个点的坐标的变量
Point2f fourPoint2f[4];
//将rectPoint变量中存储的坐标值放到 fourPoint的数组中
rectPoint.points(fourPoint2f);

//根据得到的四个点的坐标  绘制矩形
for (int i = 0; i < 3; i++)
{
line(srcImage, fourPoint2f[i], fourPoint2f[i + 1]
, Scalar(rng.uniform(0, 255), rng.uniform(0, 255), rng.uniform(0, 255)), 3);
}
line(srcImage, fourPoint2f[0], fourPoint2f[3]
, Scalar(rng.uniform(0, 255), rng.uniform(0, 255), rng.uniform(0, 255)), 3);

imshow("【绘制结束后的图像】", srcImage);

key = waitKey();
if (key == 27)
break;
else
srcImage = Scalar::all(0);
}

return 0;
}