LeetCode-Implement Queue using Stacks
2015-09-16 02:38
387 查看
这种都是用两个stack倒来倒去 注意stack peek和pop的不同 注意返回值
class MyQueue {
private Stack<Integer> s1 = new Stack<Integer>();
private Stack<Integer> s2 = new Stack<Integer>();
// Push element x to the back of queue.
public void push(int x) {
s1.push(x);
}
// Removes the element from in front of queue.
public void pop() {
if ( s2.isEmpty()){
while ( !s1.isEmpty() ){
s2.push( s1.pop() );
}
}
s2.pop();
}
// Get the front element.
public int peek() {
if ( s2.isEmpty()){
while ( !s1.isEmpty() ){
s2.push( s1.pop() );
}
}
return s2.peek();
}
// Return whether the queue is empty.
public boolean empty() {
if ( s1.empty() && s2.empty() )
return true;
else
return false;
}
}
class MyQueue {
private Stack<Integer> s1 = new Stack<Integer>();
private Stack<Integer> s2 = new Stack<Integer>();
// Push element x to the back of queue.
public void push(int x) {
s1.push(x);
}
// Removes the element from in front of queue.
public void pop() {
if ( s2.isEmpty()){
while ( !s1.isEmpty() ){
s2.push( s1.pop() );
}
}
s2.pop();
}
// Get the front element.
public int peek() {
if ( s2.isEmpty()){
while ( !s1.isEmpty() ){
s2.push( s1.pop() );
}
}
return s2.peek();
}
// Return whether the queue is empty.
public boolean empty() {
if ( s1.empty() && s2.empty() )
return true;
else
return false;
}
}
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