折半枚举(双向搜索)挑战程序设计竞赛
2015-09-07 23:13
405 查看
4 Values whose Sum is 0
Description
The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how many quadruplet (a, b, c, d ) ∈ A x B x C x D are such that a + b + c + d = 0 . In the following, we assume that all lists have the same size n .
Input
The first line of the input file contains the size of the lists n (this value can be as large as 4000). We then have n lines containing four integer values (with absolute value as large as 228 ) that belong respectively to A, B, C and D .
Output
For each input file, your program has to write the number quadruplets whose sum is zero.
Sample Input
Sample Output
Hint
Sample Explanation: Indeed, the sum of the five following quadruplets is zero: (-45, -27, 42, 30), (26, 30, -10, -46), (-32, 22, 56, -46),(-32, 30, -75, 77), (-32, -54, 56, 30).
Source
Southwestern Europe 2005
直接暴力枚举为O(n^4),二分+折半暴力枚举复杂度降为O(log n*n^2);
Time Limit: 15000MS | Memory Limit: 228000K | |
Total Submissions: 18170 | Accepted: 5343 | |
Case Time Limit: 5000MS |
The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how many quadruplet (a, b, c, d ) ∈ A x B x C x D are such that a + b + c + d = 0 . In the following, we assume that all lists have the same size n .
Input
The first line of the input file contains the size of the lists n (this value can be as large as 4000). We then have n lines containing four integer values (with absolute value as large as 228 ) that belong respectively to A, B, C and D .
Output
For each input file, your program has to write the number quadruplets whose sum is zero.
Sample Input
6 -45 22 42 -16 -41 -27 56 30 -36 53 -37 77 -36 30 -75 -46 26 -38 -10 62 -32 -54 -6 45
Sample Output
5
Hint
Sample Explanation: Indeed, the sum of the five following quadruplets is zero: (-45, -27, 42, 30), (26, 30, -10, -46), (-32, 22, 56, -46),(-32, 30, -75, 77), (-32, -54, 56, 30).
Source
Southwestern Europe 2005
直接暴力枚举为O(n^4),二分+折半暴力枚举复杂度降为O(log n*n^2);
#include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #define N 5000 using namespace std; int a , b , c , d ; int ab[N*N]; int main() { #ifdef CDZSC freopen("i.txt", "r",stdin); #endif int n; while (~scanf("%d", &n)) { int q = 0; for (int i = 0; i <n; i++) scanf("%d%d%d%d",a + i, b + i, c + i, d + i); for (int i = 0; i < n; i++) { for (int j =0 ; j < n; j++) { ab[q++] = a[i] + b[j]; } } sort(ab, ab + n*n); long long ans = 0; int cd; for (int i = 0; i <n; i++) { for (int j = 0; j < n; j++) { cd = c[i] + d[j]; ans += upper_bound(ab, ab + n*n, -cd) - lower_bound(ab, ab +n*n, -cd); } } printf("%lld\n", ans); } return 0; }
相关文章推荐
- apt-get error
- react-native试玩(14)-iOS中进度栏
- 物联网智能硬件解析之万能空调遥控器实现 Ardunio_通过红外线发射灯遥控空调
- hdu1789 Doing homework again
- uva 12167 - Proving Equivalences(强连通)
- python图像化Tkinter
- python的真值
- hdu 5015(矩阵快速幂z )
- hdu 5015(矩阵快速幂z )
- (转)这个API很“迷人”——新的Fetch API
- Python 里 immutable和hashable的概念
- ImageView的scaleType详解
- 老潘 - ListView分析 - 学以致用篇(一)
- linux运维实战练习-2015年8月30日课程作业
- android ListView 分析(一)
- 安卓中如何参考寻找和参考他人的代码(待完善和待修正)
- 高效程序员的45个习惯-敏捷开发之道 读书笔记
- 微信开发
- js单击显示元素,点击元素本身以外隐藏元素
- 【转】Android 国内集成使用谷歌地图