完美数字_华为SO挑战赛2015年8月

#include<iostream>
using namespace std;
int main()
{
int small,big;
cin>>small>>big;

int MinPerfectNum = 30;//2*3*5
int PerfectNum = 30;
int NumOfPerfectNum = 0;
for(; PerfectNum >= small && PerfectNum <= big;PerfectNum++)
{
if (PerfectNum % 2==0 && PerfectNum %3 == 0&& PerfectNum %5 == 0)
{
NumOfPerfectNum++;
}
}
cout<<NumOfPerfectNum<<endl;
system("pause");
return 0;
}