编写一个函数itob（int n,char s[],int b）,将整数n转换为以b进制的数。保存到s中

#include <stdio.h>#include <assert.h>#include <stdlib.h>#include <string.h>void swap(char *p1, char *p2){char tmp = *p1;*p1 = *p2;*p2 = tmp;}void reverse(char *pstart, char *pend){assert((pstart != NULL) && (pend != NULL));while (pstart < pend){swap(pstart, pend);pstart++;pend--;}}char *my_itob(int n, char s[], int b){char *p = s;assert(s != NULL);if (s != NULL){if (n < 0){*s == '-';n = n*(-1);s++;}while (n){*s = "0123456789abcdef"[n%b];n /= b;s++;}*s = '\0';if (*p == '-')reverse(p + 1, (p + strlen(p) - 1));elsereverse(p, (p + strlen(p) - 1));return p;}return NULL;}int main(){int num = 0;scanf("%d", &num);char output[20];char *p = my_itob(num, output, 2);printf("%s\n", p);system("pause");return 0;}