[leetcode] Implement Queue using Stacks
2015-08-08 20:37
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from : https://leetcode.com/problems/implement-queue-using-stacks/
Implement the following operations of a queue using stacks.
push(x) -- Push element x to the back of queue.
pop() -- Removes the element from in front of queue.
peek() -- Get the front element.
empty() -- Return whether the queue is empty.
Notes:
You must use only standard operations of a stack -- which means only
and
Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
Implement the following operations of a queue using stacks.
push(x) -- Push element x to the back of queue.
pop() -- Removes the element from in front of queue.
peek() -- Get the front element.
empty() -- Return whether the queue is empty.
Notes:
You must use only standard operations of a stack -- which means only
push to top,
peek/pop from top,
size,
and
is emptyoperations are valid.
Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
class MyQueue { Stack<Integer> psh = new Stack<Integer>(); Stack<Integer> pap = new Stack<Integer>(); // Push element x to the back of queue. public void push(int x) { psh.push(new Integer(x)); } // Removes the element from in front of queue. public void pop() { if (!pap.isEmpty()) { pap.pop(); } else { while (!psh.isEmpty()) { pap.push(psh.pop()); } pap.pop(); } } // Get the front element. public int peek() { if (!pap.isEmpty()) { return pap.peek(); } else { while (!psh.isEmpty()) { pap.push(psh.pop()); } return pap.peek(); } } // Return whether the queue is empty. public boolean empty() { return psh.isEmpty() && pap.isEmpty(); } }
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