POJ 2083 Fractal 递归
2015-08-07 20:00
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Fractal
Description
A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not exhibit exactly the same structure at all scales, but the same "type" of structures must appear on all scales.
A box fractal is defined as below :
A box fractal of degree 1 is simply
X
A box fractal of degree 2 is
X X
X
X X
If using B(n - 1) to represent the box fractal of degree n - 1, then a box fractal of degree n is defined recursively as following
Your task is to draw a box fractal of degree n.
Input
The input consists of several test cases. Each line of the input contains a positive integer n which is no greater than 7. The last line of input is a negative integer −1 indicating the end of input.
Output
For each test case, output the box fractal using the 'X' notation. Please notice that 'X' is an uppercase letter. Print a line with only a single dash after each test case.
Sample Input
Sample Output
Source
Shanghai 2004 Preliminary
AC代码:
Time Limit: 1000MS | Memory Limit: 30000K | |
Total Submissions: 8060 | Accepted: 3862 |
A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not exhibit exactly the same structure at all scales, but the same "type" of structures must appear on all scales.
A box fractal is defined as below :
A box fractal of degree 1 is simply
X
A box fractal of degree 2 is
X X
X
X X
If using B(n - 1) to represent the box fractal of degree n - 1, then a box fractal of degree n is defined recursively as following
B(n - 1) B(n - 1) B(n - 1) B(n - 1) B(n - 1)
Your task is to draw a box fractal of degree n.
Input
The input consists of several test cases. Each line of the input contains a positive integer n which is no greater than 7. The last line of input is a negative integer −1 indicating the end of input.
Output
For each test case, output the box fractal using the 'X' notation. Please notice that 'X' is an uppercase letter. Print a line with only a single dash after each test case.
Sample Input
1 2 3 4 -1
Sample Output
X - X X X X X - X X X X X X X X X X X X X X X X X X X X X X X X X - X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X -
Source
Shanghai 2004 Preliminary
AC代码:
#include <iostream> #include <cmath> #include <cstring> #include <algorithm> using namespace std; char map[1000][1000]; void dg(int n,int x,int y){ if(n==1){ map[x][y]='X'; return; } int m=pow(3,n-2); dg(n-1,x,y); dg(n-1,x,y+2*m); dg(n-1,x+m,y+m); dg(n-1,x+2*m,y); dg(n-1,x+2*m,y+2*m); } int main(){ int n; while(cin>>n&&n!=-1){ if(n==1){ cout<<"X\n-\n"; continue; } int m=pow(3,n-1);//cout<<"m: "<<m<<'\12'; for(int i=0;i<m;++i){ for(int j=0;j<m;++j) map[i][j]=' '; map[i][m]='\0'; } dg(n,0,0); for(int i=0;i<m;++i) cout<<map[i]<<'\12'; cout<<"-\n"; } return 0; }
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