您的位置:首页 > 其它

dda的fpga实现(转载)

2015-08-05 09:13 169 查看
The general approach using DDAs will be to simulate a system of first-order differential equations, which can be nonlinear. Analog computers use operational amplifiers to do mathematical integration. We will use digital summers and registers. For any set of differential equations with state variables
v1
to
vm
:
dv1/dt = f1(t,v1,v2,v3,...vm)
dv2/dt = f2(t,v1,v2,v3,...vm)
dv3/dt = f3(t,v1,v2,v3,...vm)
...
dvm/dt = fm(...)
We will build the following circuitry to perform an Euler integration approximation to these equations in the form
v1(n+1) = v1(n) + dt*(f1(t,v1(n),v2(n),v3(n),...vm(n))
v2(n+1) = v2(n) + dt*(f2(t,v1(n),v2(n),v3(n),...vm(n))
v3(n+1) = v3(n) + dt*(f3(t,v1(n),v2(n),v3(n),...vm(n))
...
vm(n+1) = vm(n) + dt*(fm(...))
Where the variable values at time step 
n
are updated to form the values at time step
n+1
. Each equation will require one integrator. The multiply may be replaced by a shift-right if
dt
is chosen to be a power of two. Most of the design complexity will be in calculating
F(t,V(n))
.We also need a number representation. I chose 18-bit 2's complement with the binary point between bits 15 and 16 (with bit zero being the least significant). Bit 17 is the sign bit. The number range is thus
-2.0
to
+1.999985
. This range fits well with the Audio codec which requires 16-bit 2's complement for output to the DAC. Conversion from the 18-bit to 16-bit just requires truncating the least significant two bits ([1:0]). A few numbers are shown in the table below. Note that the underscore character in the hexidecimal form is allowed in verilog to improve readability.
[align=center]Decimal number[/align]18-bit 2's comprepresentation
[align=center]1.0[/align][align=center]18'h1_0000[/align]
[align=center]0.5[/align][align=center]18'h0_8000[/align]
[align=center]0.25[/align][align=center]18'h0_4000[/align]
[align=center]0[/align][align=center]18'h0_0000[/align]
[align=center]-0.25[/align][align=center]18'h3_c000[/align]
[align=center]-0.5[/align][align=center]18'h3_8000[/align]
[align=center]-1.0[/align][align=center]18'h3_0000[/align]
[align=center]-1.5[/align][align=center]18'h2_8000[/align]
[align=center]-2.0[/align][align=center]18'h2_0000[/align]
Second order system (damped spring-mass oscillator):As an example, consider the linear, second-order differential equation resulting from a damped spring-mass system:
d2x/dt2 = -k/m*x-d/m*(dx/dt)
where k is the spring constant, d the damping coefficient, m the mass, and x the displacement. We will simulate this by converting the second-order system into a coupled first-order system. If we let
v1=x
and
v2=dx/dt
then the second order equation is equivalent to
dv1/dt = v2dv2/dt = -k/m*v1-d/m*v2
These equations can be solved by wiring together two integrators, two multipliers and an adder as shown below. In the past this would have been done by using operational amplifiers to compute each mathematical operation. Each integrator must be supplied with an initial condition.
Converting this diagram to Verilog, the top-level module verilog code defines the 18-bit, signed, state variables and a clock divider variable (
count
). The clocked section resets and updates the state variables. The combinatorial statements compute the Euler approximation to the
F(t,V(n))
. The separate multiply module ensures that the multiplies will be instantiated as hardware multipliers. The Audio_DAC_ADC module was modifed to allow either ADC-to-DAC passthru or to connect the computation output to the DAC, depending on the position of SW17. SW17 up connects the computation.
/state variablesreg signed [17:0] v1, v2 ;wire signed [17:0] v1new, v2new ;//signed mult outputwire signed [17:0] v1xK_M, v2xD_M ;// the clock dividerreg [4:0] count;//Update state variables of simulation of spring- massalways @ (posedge CLOCK_50)begincount <= count + 1;if (KEY[3]==0) //resetbeginv1 <= 32'h10000 ; //v2 <= 32'h00000 ;//count <= 0;endelse if (count==0)beginv1 <= v1new ;v2 <= v2new ;endend// Compute new F(t,v) with dt = 2>>9// v1(n+1) = v1(n) + dt*v2(n)assign v1new = v1 + (v2>>>9);// v2(n+1) = v2(n) + dt*(-k/m*v1(n) - d/m*v2(n))signed_mult K_M(v1xK_M, v1, 18'h10000);signed_mult D_M(v2xD_M, v2, 18'h00800);assign v2new = v2 - ((v1xK_M + v2xD_M)>>>9);module signed_mult (out, a, b);output 		[17:0]	out;input 	signed	[17:0] 	a;input 	signed	[17:0] 	b;wire	signed	[17:0]	out;wire 	signed	[35:0]	mult_out;assign mult_out = a * b;assign out = {mult_out[35], mult_out[32:16]};endmodule
Time scaling the solution requires consideration of the value of
dt
and the update rate (
CLOCK_50/(clock divider)
) of the state variables. As shown in the code, the clock divider variable (
count
) is 5-bits wide, so it will overflow and cause an update every 32
CLOCK_50
cycles. If the time step, dt=2-9, then 29 steps must equal one time unit. 29 steps at an update rate of 5*107/32 yields a time unit of 0.328 mSec. A k/m=1 implies a period of 6.28 time units per cycle, so one cycle in this case would be 2.06 mSec. corresponding to 486 Hz.If the calculation is scaled in time to be in the audio range, then the audio DAC may be used to watch waveforms on an oscilloscope. For the damped spring-mass oscillator with a k/m=1, d/m=1/16, dt=2-8, and a clock rate of 5*108/64 I got the figure below. The top trace is v1 and the bottom is v2. The frequency computed from the time scaling considerations is 486 Hz, while the measured was 475 Hz. Reducing
dt
to dt=2-9 (see paragraph above) and the clock divider to 32 made the measured frequency 486, matching the computed value. The better match with smaller
dt
illustrates that the integration is approximate.The whole project is zipped here. The design consumed 2% of the logic resources of the FPGA, 1% of the memory, and 4 out of 70 9-bit multipliers. You could threfore expect to put up to 50 integrators and 35 multipilers in a bigger design.
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: