EasyUi 新组件 switchbutton 根据状态切换显示内容

<script type="text/javascript">
$(function(){
$('#sbutton').switchbutton({
checked: false,
onChange: function(checked){
if (checked == true){
document.getElementById('authenTypeL').innerHTML = '已启用!';
return;
}
if (checked == false){
document.getElementById('authenTypeL').innerHTML = '未启用!';
}}
})
})
</script>

<input id="sbutton" style="width:70px;height:25px">
<label class="lblname" id="authenTypeL"></label>