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python 例子1

2015-07-24 09:43 645 查看
Python 简单的交互式操作

方法一:

#!/usr/bin/env python
#encoding:utf8
# Filename:interactive.py

name= raw_input("please input your name:")
passwd= raw_input("please input your passwd:")

count = 0
temp = 0

if name == 'liu':
if passwd == '123':
print 'welcome login!'
else:
for i in range(4):
count += i
if passwd == '123':
print 'welcome login'
break
if ( count == 3 ):
print "you passwd locked!"
else:
passwd= raw_input("please reset input your passwd:")

elif passwd == '123':
print 'true',passwd
for x in range(4):
temp += x
print 'varlue:',temp
if name == 'liu':
print 'welcome login'
break
if ( temp == 3 ):
print "you name locked"
break
else:
name= str(raw_input("please reset input your name:"))

else:
print 'name,passwd error!:'

##########################################################################################
方法二:
#!/usr/bin/python
#encoding:utf8# Filename:interactive_1.py

i = 1
while 1:

Name = raw_input("please input your name:")
Email = raw_input("please input your email:")
QQ = int(raw_input("please input your qq:"))

s2 = "{Name:[Email,QQ]}"
s3 = eval(s2)
# if s3.has_key(Name):
s3 = dict(s3.items() + s3.items())
print i
i += 1
if i > 3:
break
#s3(s3.items()) += s3(s3.items())
# else:
# raw_input("First please input your information! Enter")
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