for练习--凑法

static void Main14购物卡(string[] args)
{
//小明单位发了50元的购物卡，他到超市买洗化用品，一是牙刷（5元），二是香皂（2元），三是牙膏（10元）怎么可以正好把五十元花完。

for (int i = 0; i <= 10; i++)
{

for (int x = 0; x <= 25; x++)
{
for (int g = 0; g <= 5; g++)
{
if (i * 5 + x * 2 + g * 5 == 50)
{
Console.WriteLine("牙刷\t" + i + "个，香皂\t" + x + "个，牙膏\t" + g + "个");
}
}
}
}
}

static void Main15白文白鸡(string[] args)
{
//公鸡两文/只，母鸡一文/只，小鸡半文/只，花100文钱，买100只鸡，该如何购买？
Console.WriteLine("买法有：");
int n = 0;
for (int a = 0; a <= 50; a++)
{
for (int b = 0; b <= 100; b++)
{
for (int c = 0; c <= 200; c++)
{
if (a + b + c == 100 && a * 2 + b * 1 + c * 0.5 == 100)
{
n++;
Console.WriteLine("公鸡" + a + "母鸡" + b + "小鸡" + c);
}
}
}
}
Console.WriteLine("共有{0}种买法", n);
}

static void Main16白马百担(string[] args)
{
//白马百担：大马驮2担粮食，中马驮1担粮食，两头小马驮1担粮食，要用100匹马，驮100担粮食，该如何调配？
int n = 0;
for (int a = 0; a <= 50; a++)
{
for (int b = 0; b <= 100; b++)
{
for (int c = 0; c <= 200; c++)
{
if (a + b + c == 100 && a * 2 + b * 1 + c * 0.5 == 100)
{
n++;
Console.WriteLine("大马{0}\t中马{1}\t小马{2}", a, b, c);
}
}
}
}
Console.WriteLine("共有{0}种驮法", n);

}

static void Main17凑钱(string[] args)
{
//有1块、2块、5块的钱若干，凑出20块，有几种凑法？

int n = 0;
for (int a = 0; a <= 20; a++)
{
for (int b = 0; b <= 10; b++)
{
for (int c = 0; c <= 4; c++)
{
if (a * 1 + b * 2 + c * 5 == 20)
{
n++;
Console.WriteLine("一块的{0}，2块的{1}，五块的{2}", a, b, c);
}
}
}
}
Console.WriteLine("共有{0}种凑法", n);
}