android 返回键两次退出

private long exitTime = 0;
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if(keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN){
if((System.currentTimeMillis()-exitTime) > 2000){
Toast.makeText(getApplicationContext(), "再按一次退出程序", Toast.LENGTH_SHORT).show();
exitTime = System.currentTimeMillis();
} else {
finish();
android.os.Process.killProcess(android.os.Process.myPid()); //获取PID
System.exit(0);
}
return true;
}
return super.onKeyDown(keyCode, event);
}