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Uva - 714 - Copying Books

2015-06-21 22:25 357 查看


把问题转换为把输入序列划分成m个连续的子序列,s.t 所有的S(i)均不超过x。然后二分最小值。

AC代码:

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cctype>
#include <cstring>
#include <string>
#include <sstream>
#include <vector>
#include <set>
#include <map>
#include <algorithm>
#include <stack>
#include <queue>
#include <bitset>
#include <cassert>
#include <cmath>

using namespace std;

const int maxm = 505;
int k, m;
int p[maxm];

// 在maxp的限制下最多需要多少scribers
int solve(long long maxp)
{
long long done = 0;
int ans = 1;
for (int i = 0; i < m; i++) {
if (done + p[i] <= maxp) {
done += p[i];
}
else {
ans++;
done = p[i];
}
}
return ans;
}

int last[maxm];
// 贪心输出结果
void print(long long ans)
{
long long done = 0;
memset(last, 0, sizeof(last));
int remain = k;
for (int i = m - 1; i >= 0; i--) {
if (done + p[i] > ans || i + 1 < remain) {
last[i] = 1;
remain--;
done = p[i];
}
else {
done += p[i];
}
}
for (int i = 0; i < m - 1; i++) {
cout << p[i] << " ";
if (last[i]) {
cout << "/ ";
}
}
cout << p[m - 1] << endl;
}

int main()
{
ios::sync_with_stdio(false);
int n;
cin >> n;
while (n--) {
cin >> m >> k;
long long tot = 0; // 总和
int maxp = -1; // 最大值
for (int i = 0; i < m; i++) {
cin >> p[i];
tot += p[i];
maxp = max(maxp, p[i]);
}
long long L = maxp, R = tot;
// 二分最小值
while (L < R) {
long long M = L + (R - L) / 2;
if (solve(M) <= k) {
R = M;
}
else {
L = M + 1;
}
}
print(L);
}

return 0;
}
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