B - Soldier and Badges (CF546B) Codeforces Round #304 (Div. 2)

B. Soldier and Badges

time limit per test
3 seconds

memory limit per test
256 megabytes

input
standard input

output
standard output

Colonel has n badges. He wants to give one badge to every of his n soldiers.
Each badge has a coolness factor, which shows how much it's owner reached. Coolness factor can be increased by one for the cost of one coin.

For every pair of soldiers one of them should get a badge with strictly higher factor than the second one. Exact values of their factors aren't important, they just need to have distinct factors.

Colonel knows, which soldier is supposed to get which badge initially, but there is a problem. Some of badges may have the same factor of coolness. Help him and calculate how much money has to be paid for making all badges have different factors of coolness.

Input

First line of input consists of one integer n (1 ≤ n ≤ 3000).

Next line consists of n integers ai (1 ≤ ai ≤ n),
which stand for coolness factor of each badge.

Output

Output single integer — minimum amount of coins the colonel has to pay.

Sample test(s)

input

4
1 3 1 4

output

1

input

5
1 2 3 2 5

output

2

Note

In first sample test we can increase factor of first badge by 1.

In second sample test we can increase factors of the second and the third badge by 1.

题意：给你n堆价值，要求得到每堆价值是独一无二的，问你往每堆加多少，最少加多少。

思路：（贪心）先排序，然后以第一个为基准，后面的不大于前面的，就加加；

转载请注明出处：寻找&星空の孩子

题目链接：http://codeforces.com/contest/546/problem/B

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <string>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <vector>
#include <math.h>
#include <bitset>
#include <list>
#include <algorithm>
#include <climits>
using namespace std;

#define lson 2*i
#define rson 2*i+1
#define LS l,mid,lson
#define RS mid+1,r,rson
#define UP(i,x,y) for(i=x;i<=y;i++)
#define DOWN(i,x,y) for(i=x;i>=y;i--)
#define MEM(a,x) memset(a,x,sizeof(a))
#define W(a) while(a)
#define gcd(a,b) __gcd(a,b)
#define LL long long
#define N 5000005
#define INF 0x3f3f3f3f
#define EXP 1e-8
#define lowbit(x) (x&-x)
const int mod = 1e9+7;
#define LL __int64
int n,a[3005];
int main()
{
    int i,j,ans;
    while(~scanf("%d",&n))
    {
        ans = 0;
        int sum1 = 0,sum2 = 0;
        for(i = 1; i<=n; i++)
        {
            scanf("%d",&a[i]);
            sum1+=a[i];
        }
        sort(a+1,a+1+n);
        sum2 = a[1];
        for(i = 2; i<=n; i++)
        {
            if(a[i] == a[i-1])
                a[i]++;
            else if(a[i]<a[i-1])
                a[i] +=(a[i-1]-a[i])+1;
            sum2+=a[i];
        }
        printf("%d\n",sum2-sum1);
    }

    return 0;
}