IBM 3624 Customer PIN,Natural PIN,PIN Offset的相关内容

IBM 3624 Customer PIN,Natural PIN,PIN Offset的相关内容

以下描述了利用IBM 3624产生k位用户pin的方法

1.用PIN Verification Key (PVK)加密PAN（Primary Account Number）最右16位，产生16位十六进制字符串；

2.利用Decimalisation Table = 0123456789012345，将第1步结果转换为10机制数，例如：
HEX 0 1 2 3 4 5 6 7 8 9 A B C D E F
DECIMAL
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5

3. 取第2步结果的前k位，即可得到k为Natural PIN

4. Natural PIN加上PIN Offset值就得到了Customer PIN（注意：位加不进位，即：no-carry-addition）；

5. 相反PIN Offset为Customer PIN减去Natural PIN（注意：位减不借位，即：no-borrows-subtraction）. 

Examples 1:

Account: 1234567890123456

PVK: 1313131313131313

Decimalisation Table: 0123456789012345 , ie. 0(Hex) = 0, B(Hex) = 1, etc.

PIN length:k=6

Then the result of step 1 = 64DA85B3795AE4E4

Result of step 2 = 6430851379504444 (decimal)

Then Natural PIN = 643085

(1) Let PIN Offset be 456789
 Customer PIN
= 643085 + 456789 (no carry-over on each digit) = 099764

(2) Let PIN Offset be 000000
 Customer PIN
= 643085 + 000000 (no carry-over on each digit) = 643085

Examples 2:

Card number: 1234567890123445

PIN key: 0123456789ABCDEF

Encrypted card number: 9A466AD30DFE0381

Natural PIN: 9046.

Offset: 2298 (this number is written on track 3).

Customer PIN: 1234.

PIN Offset通常写在第三磁道

参考文档：
http://www.gae.ucm.es/~padilla/extrawork/magexam1.html http://www-01.ibm.com/support/knowledgecenter/SSLTBW_2.1.0/com.ibm.zos.v2r1.csfb400/csfb4za2597.htm%23wq3968