输入一串字符串，其中有普通的字符与括号组成（包括‘（’、‘）’、‘[’,']'）,要求验证括号是否匹配，如果匹配则输出0、否则输出1.

#include <stdio.h>

int push(char *pstr, char *dstr );

int main()
{
char *str = "]d)]fa(sdf)df[dfds(dfd)] ()*()";

char data[50];

int flag = -5;

flag = push(str,data);

if(flag == -1)
printf("%d\n",0);
else
printf("%d\n",1);

}

int push(char *pstr, char *dstr )
{
int i = 0, j = -1;

if(pstr == NULL)
return -2;

while(pstr[i] !='\0')
{
if(pstr[i] == '(' || pstr[i] == '[')
{
j++;
dstr[j] = pstr[i];
}
else
{
if(pstr[i] == ')' )
{
if(j == -1)
{
return j+1;
}
else
{
if(dstr[j] == '(')
j--;
else
{
j++;
dstr[j] = pstr[i];
}
}
}
if(pstr[i] == ']')
{
if(j == -1)
{
return j+1;
}
else
if(dstr[j] == '[')
j--;
else
{
j++;
dstr[j] = pstr[i];
}
}
}
i++;
}

return j;

}