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Java 分治算法实现排序数索引(二分搜索)

2015-06-08 17:49 591 查看
/**
* Find the first q and return the index
* First method is brutal force
* Second may
* be Divid and Conquer
*
* @author open201
*
*/
public class Ono {
/**
* f(n) = s.length = n;
*
* @param s
* @param q
* @return
*/
public static int BrutalForceSearch(int[] s, int q) {
for (int i = 0; i < s.length; i++) {
if (q == s[i])
return i;
}
return -1;
}

/**
* f(n) = log(n)
*
* @param s
* @param q
* @return
*/
public static int DCSearch(int[] s, int q, int startIndex, int endIndex) {
if (startIndex > endIndex)
return -1;
else {
int mid = (startIndex + endIndex) / 2;
if (s[mid] == q)
return mid;
else {
if (s[mid] > q)
return DCSearch(s, q, startIndex,mid-1);
else
return DCSearch(s, q, mid+ 1,endIndex);
}
}
}

public static void main(String[] args) {
int [] s = new int[10000000];
for(int i = 0;i<10000000;i++){
s[i] = i;
}
int q = 10000000-1;

long startTime = System.currentTimeMillis();
System.out.println(BrutalForceSearch(s, q));
long endTime = System.currentTimeMillis();

System.out.println(endTime-startTime);

startTime = System.currentTimeMillis();
System.out.println(DCSearch(s, q, 0, s.length - 1));
endTime = System.currentTimeMillis();

System.out.println(endTime-startTime);
}
}
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