PAT 1002 Hello World for U (20)
2015-06-06 09:05
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Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld"
can be printed as:
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters,
then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n1 = n3 = max { k| k <= n2 for all 3
<= n2 <= N } with n1 + n2 + n3 - 2 = N.
输入描述:
输出描述:
输入例子:
输出例子:
插个图
can be printed as:
h d e l l r lowo
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters,
then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n1 = n3 = max { k| k <= n2 for all 3
<= n2 <= N } with n1 + n2 + n3 - 2 = N.
输入描述:
Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.
输出描述:
For each test case, print the input string in the shape of U as specified in the description.
输入例子:
helloworld!
输出例子:
h ! e d l l lowor
#include <iostream> #include <cstring> #include <string> using namespace std; int main() { int i1,i2,left_right,down,i,j,k; char s[1024]; while(cin>>s) { i1=(strlen(s)+2)/3; i2=(strlen(s)+2)%3; if(1==i2) { left_right=i1; down=i1+1; } else if(2==i2) { left_right=i1; down=i1+2; } else { left_right=down=i1; } for(i=0,k=0;i<left_right-1;i++) { cout<<s[k]; for(j=2;j<down;j++) cout<<" "; cout<<s[strlen(s)-1-k]<<endl; k++; } for(i=k;i<strlen(s)-k;i++) cout<<s[i]; cout<<endl; } return 0; }
插个图
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