error: invalid conversion from ‘void (*)()’ to ‘void (*)(int)’

void signaldemo_test(void)
{
struct itimerval tv, otv;
signal(SIGALRM, sigFunc);

//how long to run the first time
tv.it_value.tv_sec = 3;
tv.it_value.tv_usec = 0;

//after the first time, how long to run next time
tv.it_interval.tv_sec = 5;
tv.it_interval.tv_usec = 0;

if (setitimer(ITIMER_REAL, &tv, &otv) != 0)     //定时每隔5s执行一次
{
printf("setitimer err %d\n", errno);
}

while(1)
{
sleep(2);

//隔2s打印一遍
printf("otv: %d, %d, %d, %d\n", otv.it_value.tv_sec, otv.it_value.tv_usec, otv.it_interval.tv_sec, otv.it_interval.tv_sec);
}
}

void sigFunc()
{
static int iCnt = 0;    printf("The %d Times: my girl maybe in SZ library \n", iCnt++);}

}

以上这段代码在用g++编译是会有如下错误：
/mnt/hgfs/Linux/cleanCup/src/signaldemo.cpp:9: error: invalid conversion from ‘void (*)()’ to ‘void (*)(int)’
/mnt/hgfs/Linux/cleanCup/src/signaldemo.cpp:9: error:   initializing argument 2 of ‘void (* signal(int, void (*)(int)))(int)’

值得注意的是在gcc编译时不会出错，但是用g++就会有问题，究其原因就是C语言编译器允许隐含性的将一个通用指针转换为任意类型的指针，而C＋＋不允许。

void sigFunc(int)
{
static int iCnt = 0;    printf("The %d Times: my girl maybe in SZ library \n", iCnt++);}

}