leetcode - ZigZag Conversion
2015-05-17 23:07
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转自:/article/6347759.html
题目:
The string
this: (you may want to display this pattern in a fixed font for better legibility)
And then read line by line:
Write the code that will take a string and make this conversion given a number of rows:
return
Zigzag:即循环对角线结构(
)
nRows行,声明nRows个字符串,每个字符串存储自己行的字符
向下循环:nRows
斜角线向上循环: 从nRows-2 开始,1 结束 (减去首尾两个端点)
重复
...
题目:
The string
"PAYPALISHIRING"is written in a zigzag pattern on a given number of rows like
this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line:
"PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3)should
return
"PAHNAPLSIIGYIR"
Zigzag:即循环对角线结构(
0 | 8 | 16 | |||||||||
1 | 7 | 9 | 15 | 17 | |||||||
2 | 6 | 10 | 14 | 18 | |||||||
3 | 5 | 11 | 13 | 19 | |||||||
4 | 12 | 20 |
nRows行,声明nRows个字符串,每个字符串存储自己行的字符
向下循环:nRows
斜角线向上循环: 从nRows-2 开始,1 结束 (减去首尾两个端点)
重复
...
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