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第八周项目1-实现复数类中的运算符重载(3)

2015-05-16 10:57 417 查看
问题及代码:
/*
*Copyright(c)2014,烟台大学计算学院
*All  rights reserved.
*文件名称:test.cpp
*作者:陈银丽
*完成日期:2015年5月16日
*版本号:v1.0
*
/*问题描述:定义一个定义完整的类(使可以当作独立的产品发布,成为众多项目中的基础工程)这样的类在(2)的基础上,拓展+,-,*,/,
运算符的功能,使之能与double型数据进行运算。设comple c;c+d,d+c的结果为将d视为实部为d的复数同c相加,其他类似
*输入描述:

*程序输出:
*/
#include <iostream>
using namespace std;
class Complex
{
public:
Complex()
{
real=0;
imag=0;
}
Complex(double r,double i)
{
real=r;
imag=i;
}
friend Complex operator+(Complex &c1, Complex &c2);
friend Complex operator+(double d1, Complex &c2);
friend Complex operator+(Complex &c1, double d2);
friend Complex operator-(Complex &c1, Complex &c2);
friend Complex operator-(double d1, Complex &c2);
friend Complex operator-(Complex &c1, double d2);
friend Complex operator*(Complex &c1, Complex &c2);
friend Complex operator*(double d1, Complex &c2);
friend Complex operator*(Complex &c1, double d2);
friend Complex operator/(Complex &c1, Complex &c2);
friend Complex operator/(double d1, Complex &c2);
friend Complex operator/(Complex &c1, double d2);
void display();
private:
double real;
double imag;
};

//复数相加:(a+bi)+(c+di)=(a+c)+(b+d)i.
Complex operator+(Complex &c1, Complex &c2)
{
Complex c;
c.real=c1.real+c2.real;
c.imag=c1.imag+c2.imag;
return c;
}
Complex operator+(double d1, Complex &c2)
{
Complex c(d1,0);
return c+c2;
}
Complex operator+(Complex &c1, double d2)
{
Complex c(d2,0);
return c1+c;
}
//复数相减:(a+bi)-(c+di)=(a-c)+(b-d)i.
Complex operator-(Complex &c1, Complex &c2)
{
Complex c;
c.real=c1.real-c2.real;
c.imag=c1.imag-c2.imag;
return c;
}
Complex operator-(double d1, Complex &c2)
{
Complex c(d1,0);
return c-c2;
}
Complex operator-(Complex &c1, double d2)
{
Complex c(d2,0);
return c1-c;
}

//复数相乘:(a+bi)(c+di)=(ac-bd)+(bc+ad)i.
Complex operator*(Complex &c1, Complex &c2)
{
Complex c;
c.real=c1.real*c2.real-c1.imag*c2.imag;
c.imag=c1.imag*c2.real+c1.real*c2.imag;
return c;
}
Complex operator*(double d1, Complex &c2)
{
Complex c(d1,0);
return c*c2;
}
Complex operator*(Complex &c1, double d2)
{
Complex c(d2,0);
return c1*c;
}

//复数相除:(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i
Complex operator/(Complex &c1, Complex &c2)
{
Complex c;
c.real=(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
c.imag=(c1.imag*c2.real-c1.real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
return c;
}
Complex operator/(double d1, Complex &c2)
{
Complex c(d1,0);
return c/c2;
}
Complex operator/(Complex &c1, double d2)
{
Complex c(d2,0);
return c1/c;
}

void Complex::display()
{
cout<<"("<<real<<","<<imag<<"i)"<<endl;
}

int main()
{
Complex c1(3,4),c2(5,-10),c3;
double d=11;
cout<<"c1=";
c1.display();
cout<<"c2=";
c2.display();
cout<<"d="<<d<<endl<<endl;
cout<<"下面是重载运算符的计算结果: "<<endl;
c3=c1+c2;
cout<<"c1+c2=";
c3.display();
cout<<"c1+d=";
(c1+d).display();
cout<<"d+c1=";
(d+c1).display();
c3=c1-c2;
cout<<"c1-c2=";
c3.display();
cout<<"c1-d=";
(c1-d).display();
cout<<"d-c1=";
(d-c1).display();
c3=c1*c2;
cout<<"c1*c2=";
c3.display();
cout<<"c1*d=";
(c1*d).display();
cout<<"d*c1=";
(d*c1).display();
c3=c1/c2;
cout<<"c1/c2=";
c3.display();
cout<<"c1/d=";
(c1/d).display();
cout<<"d/c1=";
(d/c1).display();
return 0;
}

运行结果:



知识点总结:用不同的函数实现复数类的运算符重载
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