HDU4706——Children's Day（简单模拟）

#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
printf("a e\n");
printf("bdf\n");
printf("c g\n");

printf("h  n\n");
printf("i mo\n");
printf("jl p\n");
printf("k  q\n");

printf("r   z\n");
printf("s  ya\n");
printf("t x b\n");
printf("uw  c\n");
printf("v   d\n");

printf("e    o\n");
printf("f   np\n");
printf("g  m q\n");
printf("h l  r\n");
printf("ik   s\n");
printf("j    t\n");

printf("u     g\n");
printf("v    fh\n");
printf("w   e i\n");
printf("x  d  j\n");
printf("y c   k\n");
printf("zb    l\n");
printf("a     m\n");

printf("n      b\n");
printf("o     ac\n");
printf("p    z d\n");
printf("q   y  e\n");
printf("r  x   f\n");
printf("s w    g\n");
printf("tv     h\n");
printf("u      i\n");

printf("j       z\n");
printf("k      ya\n");
printf("l     x b\n");
printf("m    w  c\n");
printf("n   v   d\n");
printf("o  u    e\n");
printf("p t     f\n");
printf("qs      g\n");
printf("r       h\n");

printf("i        a\n");
printf("j       zb\n");
printf("k      y c\n");
printf("l     x  d\n");
printf("m    w   e\n");
printf("n   v    f\n");
printf("o  u     g\n");
printf("p t      h\n");
printf("qs       i\n");
printf("r        j\n");
return 0;
}

#include <iostream>
#include <cstdio>
using namespace std;

char str[100][100];

int main(){
    int cnt = 0;

    for(int i = 3;i <= 10;i++){
        for(int j = 0;j < i;j++){
            for(int k = 0;k < i;k++)
                str[j][k] = ' ';
            str[j][i] = 0;
        }
        for(int j = 0;j < i;j++){
            str[j][0] = 'a' + cnt;
            cnt = (cnt+1)%26;
        }
        for(int j = i-2;j > 0;j--){
            str[j][i-1-j] = 'a' + cnt;
            cnt = (cnt+1)%26;
        }
        for(int j = 0;j < i;j++){
            str[j][i-1] = 'a' + cnt;
            cnt = (cnt+1)%26;
        }
        for(int j = 0;j < i;j++)
            printf("%s\n",str[j]);
    }

    return 0;
}

#include <stdio.h>
const int N = 26;

int solve(int n, int c){
    int dist = 2 * (n - 1);
    for (int i = 0; i < n; i++){
        for (int j = 0; j < n; j++){
            if (j == 0)
                printf("%c", 'a' + (c + i) % N);
            else if(j == n - 1)
                printf("%c", 'a' + (c + i + dist) % N);
            else if(i + j == n - 1)
                printf("%c", 'a' + (i + c + (n - i - 1) * 2) % N);
            else
                printf(" ");
        }
        printf("\n");
    }
}

int main(){
    int t = 0;
    for (int i = 3; i <= 10; i++){
        solve(i, t);
        t += i * 3 - 2;
    }
    return 0;
}