紫薯e5-2 uva101 the blocks problem
2015-04-30 09:20
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The Blocks Problem
Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld & %llu
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Description
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Background
Many areas of Computer Science use simple, abstract domains for both analytical and empirical studies. For example, an early AI study of planning and robotics (STRIPS) used a block world in which a robot arm performed tasks involving the manipulation of blocks.
In this problem you will model a simple block world under certain rules and constraints. Rather than determine how to achieve a specified state, you will “program” a robotic arm to respond to a limited set of commands.
The Problem
The problem is to parse a series of commands that instruct a robot arm in how to manipulate blocks that lie on a flat table. Initially there are n blocks on the table (numbered from 0 to n-1) with block bi adjacent to block bi+1 for all 0≤i<n−1 as shown in the diagram below:
\begin{figure} \centering \setlength{\unitlength}{0.0125in} % \begin{picture} (2... ...raisebox{0pt}[0pt][0pt]{$\bullet \bullet \bullet$ }}} \end{picture} \end{figure}
Figure: Initial Blocks World
The valid commands for the robot arm that manipulates blocks are:
•move a onto b
where a and b are block numbers, puts block a onto block b after returning any blocks that are stacked on top of blocks a and b to their initial positions.
•move a over b
where a and b are block numbers, puts block a onto the top of the stack containing block b, after returning any blocks that are stacked on top of block a to their initial positions.
•pile a onto b
where a and b are block numbers, moves the pile of blocks consisting of block a, and any blocks that are stacked above block a, onto block b. All blocks on top of block b are moved to their initial positions prior to the pile taking place. The blocks stacked above block a retain their order when moved.
•pile a over b
where a and b are block numbers, puts the pile of blocks consisting of block a, and any blocks that are stacked above block a, onto the top of the stack containing block b. The blocks stacked above block a retain their original order when moved.
•quit
terminates manipulations in the block world.
Any command in which a = b or in which a and b are in the same stack of blocks is an illegal command. All illegal commands should be ignored and should have no affect on the configuration of blocks.
The Input
The input begins with an integer n on a line by itself representing the number of blocks in the block world. You may assume that 0 < n < 25.
The number of blocks is followed by a sequence of block commands, one command per line. Your program should process all commands until the quit command is encountered.
You may assume that all commands will be of the form specified above. There will be no syntactically incorrect commands.
The Output
The output should consist of the final state of the blocks world. Each original
4000
block position numbered i ( 0≤i<n where n is the number of blocks) should appear followed immediately by a colon. If there is at least a block on it, the colon must be followed by one space, followed by a list of blocks that appear stacked in that position with each block number separated from other block numbers by a space. Don’t put any trailing spaces on a line.
There should be one line of output for each block position (i.e., n lines of output where n is the integer on the first line of input).
Sample Input
10
move 9 onto 1
move 8 over 1
move 7 over 1
move 6 over 1
pile 8 over 6
pile 8 over 5
move 2 over 1
move 4 over 9
quit
Sample Output
0: 0
1: 1 9 2 4
2:
3: 3
4:
5: 5 8 7 6
6:
7:
8:
9:
2、解题思路:
因为是若干堆,所以用vector记录更方便,因为有pile[i][j]可以直接访问第i堆得第j个数;而用stack的话则在数在堆间转移的过程中需要另一个stack维护顺序;
对于四个操作中都有的动作,我们可以单独摘出编写子函数。程序中注意resize()的用法,注意size()后有括号。
Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld & %llu
Submit
Status
Description
Download as PDF
Background
Many areas of Computer Science use simple, abstract domains for both analytical and empirical studies. For example, an early AI study of planning and robotics (STRIPS) used a block world in which a robot arm performed tasks involving the manipulation of blocks.
In this problem you will model a simple block world under certain rules and constraints. Rather than determine how to achieve a specified state, you will “program” a robotic arm to respond to a limited set of commands.
The Problem
The problem is to parse a series of commands that instruct a robot arm in how to manipulate blocks that lie on a flat table. Initially there are n blocks on the table (numbered from 0 to n-1) with block bi adjacent to block bi+1 for all 0≤i<n−1 as shown in the diagram below:
\begin{figure} \centering \setlength{\unitlength}{0.0125in} % \begin{picture} (2... ...raisebox{0pt}[0pt][0pt]{$\bullet \bullet \bullet$ }}} \end{picture} \end{figure}
Figure: Initial Blocks World
The valid commands for the robot arm that manipulates blocks are:
•move a onto b
where a and b are block numbers, puts block a onto block b after returning any blocks that are stacked on top of blocks a and b to their initial positions.
•move a over b
where a and b are block numbers, puts block a onto the top of the stack containing block b, after returning any blocks that are stacked on top of block a to their initial positions.
•pile a onto b
where a and b are block numbers, moves the pile of blocks consisting of block a, and any blocks that are stacked above block a, onto block b. All blocks on top of block b are moved to their initial positions prior to the pile taking place. The blocks stacked above block a retain their order when moved.
•pile a over b
where a and b are block numbers, puts the pile of blocks consisting of block a, and any blocks that are stacked above block a, onto the top of the stack containing block b. The blocks stacked above block a retain their original order when moved.
•quit
terminates manipulations in the block world.
Any command in which a = b or in which a and b are in the same stack of blocks is an illegal command. All illegal commands should be ignored and should have no affect on the configuration of blocks.
The Input
The input begins with an integer n on a line by itself representing the number of blocks in the block world. You may assume that 0 < n < 25.
The number of blocks is followed by a sequence of block commands, one command per line. Your program should process all commands until the quit command is encountered.
You may assume that all commands will be of the form specified above. There will be no syntactically incorrect commands.
The Output
The output should consist of the final state of the blocks world. Each original
4000
block position numbered i ( 0≤i<n where n is the number of blocks) should appear followed immediately by a colon. If there is at least a block on it, the colon must be followed by one space, followed by a list of blocks that appear stacked in that position with each block number separated from other block numbers by a space. Don’t put any trailing spaces on a line.
There should be one line of output for each block position (i.e., n lines of output where n is the integer on the first line of input).
Sample Input
10
move 9 onto 1
move 8 over 1
move 7 over 1
move 6 over 1
pile 8 over 6
pile 8 over 5
move 2 over 1
move 4 over 9
quit
Sample Output
0: 0
1: 1 9 2 4
2:
3: 3
4:
5: 5 8 7 6
6:
7:
8:
9:
2、解题思路:
因为是若干堆,所以用vector记录更方便,因为有pile[i][j]可以直接访问第i堆得第j个数;而用stack的话则在数在堆间转移的过程中需要另一个stack维护顺序;
对于四个操作中都有的动作,我们可以单独摘出编写子函数。程序中注意resize()的用法,注意size()后有括号。
#include <iostream> #include<cstring> #include<vector> using namespace std; /* run this program using the console pauser or add your own getch, system("pause") or input loop */ const int maxm=30; int n; typedef vector<int> v; v pile[maxm]; void find(int a,int&h,int&p){ for(p=0;p<n;p++){ for(h=0;h<pile[p].size();h++){ if(pile[p][h]==a)return; } } } void clr(int p,int h){ for(int i=h+1;i<pile[p].size();i++){ int b=pile[p][i]; pile[b].push_back(b); } pile[p].resize(h+1);//改变 大小,其余自动删去。 } void po(int p,int h,int p2){ for(int i=h;i<pile[p].size();i++){ pile[p2].push_back(pile[p][i]); } pile[p].resize(h); } void mab(int pa,int ha,int pb,int hb){ clr(pa,ha); clr(pb,hb); po(pa,ha,pb); } void mabv(int pa,int ha,int pb,int hb){ clr(pa,ha); po(pa,ha,pb); } void pab(int pa,int ha,int pb,int hb ){ clr(pb,hb); po(pa,ha,pb); } void pabv(int pa,int ha,int pb,int hb ){ po(pa,ha,pb); } void print (){ for(int i=0;i<n;i++){ cout<<i<<': '<<endl; for(int j=0;j<pile[i].size();j++){ cout<<pile[i][j]; } cout<<endl; } } int main(int argc, char** argv) { cin>>n; int a,b; string s1,s2; for(int i=0;i<n;i++){ pile[i].push_back(i); } while(cin>>s1>>a>>s2>>b){ int pa,pb,ha,hb; find(a,ha,pa); find(b,hb,pb); if(pa==pb)continue; if(s1=="move"){ if(s2=="onto")mab(pa,ha,pb,hb); else mabv(pa,ha,pb,hb); } else { if(s2=="onto")pab(pa,ha,pb,hb); else pabv(pa,ha,pb,hb); } } print(); return 0; }
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