C#结合JavaScript实现秒杀倒计时的方法

本文实例讲述了C#结合JavaScript实现秒杀倒计时的方法。分享给大家供大家参考。具体如下：

最近做个秒杀活动，要用到倒计时。要求每周三上午10:00开始倒计时

private string Dtime()
{
byte tempB = (byte)DateTime.Now.DayOfWeek;
byte dayByte = (byte)DayOfWeek.Wednesday;
DateTime wednesdayNow = DateTime.Now.AddDays(dayByte - tempB);
//本星期三
DateTime returnTime = new DateTime ();
if (DateTime.Now.DayOfWeek < wednesdayNow.DayOfWeek)
{
//当前星期小于本星期三 获取本周星期三
returnTime = new DateTime(wednesdayNow.Year,wednesdayNow.Month,wednesdayNow.Day,10,0,0);
}
else
{
//当前星期大于本星期三 获取下周星期三
DateTime nextWednesday = wednesdayNow.AddDays(7);//下周三
returnTime = new DateTime(nextWednesday.Year,nextWednesday.Month,nextWednesday.Day,10,0,0);
}
return returnTime.ToString()
}

这个方法可以得到每周三的时间，然后用js对该时间进行倒计时

$(document).ready(function() {
$('body').everyTime('1s', function() {
var nowDate = new Date();
var endDate = new Date($("#sp_next").html().replace(//-/g, "//"));
//这个时间是上个方法返回的时间
var timeold = endDate.getTime() - nowDate.getTime();
var sectimeold = timeold / 1000
var secondsold = Math.floor(sectimeold);
var msPerDay = 24 * 60 * 60 * 1000
var e_daysold = timeold / msPerDay
var daysold = Math.floor(e_daysold);
var e_hrsold = (e_daysold - daysold) * 24 + (daysold * 24);
var hrsold = Math.floor(e_hrsold);
var e_minsold = (e_hrsold - hrsold) * 60;
var minsold = Math.floor((e_hrsold - hrsold) * 60);
var seconds = Math.floor((e_minsold - minsold) * 60);
if (hrsold > 0 && hrsold < 10) { hrsold = "0" + hrsold; }
if (minsold < 10) { minsold = "0" + minsold; }
if (seconds < 10) { seconds = "0" + seconds; }
if (hrsold < 0) {
$(".seckill_time").html("0");
$(".seckill_minute").html("0");
$(".seckill_second").html("0");
} else {
$(".seckill_time").html("").html(hrsold);
$(".seckill_minute").html("").html(minsold);
$(".seckill_second").html("").html(seconds);
}
});
});

希望本文所述对大家的C#程序设计有所帮助。

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