继承中派生类指针转换为基类指针

#include "stdafx.h"
#include <memory>
using namespace std;

class Base
{
public:
Base(){}
~Base(){}

virtual void Deal()
{
int n;
n = 6;
}
private:
};

class A : public Base
{
public:
A(){}
~A(){}

virtual void Deal() override
{
int i;
i = 1;
}

void xxxx()
{

}
private:
};

int _tmain(int argc, _TCHAR* argv[])
{
shared_ptr<A> a(new A());
shared_ptr<Base> p = a;
p->Deal();//ok,继承覆盖了基类Deal函数

p->xxxx();//class "Base" 没有成员 "xxxx"

return 0;
}

如何才能调用继承类(A类)的成员函数xxxx呢?

转换方法:

shared_ptr<A> sp = dynamic_point_cast<A>(p);

智能指针用:dynamic_pointer_cast,

一般指针用:dynamic_cast