Arduino中LED灯实现256中颜色的渐变

根据颜色由三原色组成，根据其混成比例编写了此代码，实现了356种颜色的渐变过程；

//colort test;const int red = 9;const int green =10;const int blue = 11;void setup() {{pinMode(red, OUTPUT);pinMode(green, OUTPUT);pinMode(blue, OUTPUT);}}void loop() {//总共有8*8*4=256种颜色；for(double r=0.125; r<=1.0; r+=0.125)   //8for(double g=0.125; g<=1.0; g+=0.125) //8for(double b=0.25; b<=1.0; b+=0.25) //4{double k1=g/r;    //比例系数；double k2=b/r;for(double number=1.0; number<=255.0; number+=1.0) //同比例增加；{double R=number;double G=k1*R;double B=k2*R;if( R>254 )        //判断增加的值是否大于最大值255，如果是则停止增加，慢慢变暗；否则继续增加；{for( double R=255.0; R>0.0;R-=1.0){if(R<=1.0)break;else{double G=k1*R;double B=k2*R;analogWrite(red,R);analogWrite(green,G);analogWrite(blue,B);delay(20);}}break;}else if( G>254 ){for( double G=255.0; G>0.0;G-=1.0){if(G<=1.0)break;else{double R=G/k1;double B=k2*R;analogWrite(red,R);analogWrite(green,G);analogWrite(blue,B);delay(20);}}break;}else if( B > 254 ){for( double B=255.0; B>0.0;B-=1.0){if(B<=1.0)break;else{double R=B/k2;double G=k1*R;analogWrite(red,R);analogWrite(green,G);analogWrite(blue,B);delay(20);}}break;}else{analogWrite(red,R);analogWrite(green,G);analogWrite(blue,B);delay(20);}}}}