LeetCode | #27 Remove Element
2015-03-09 16:37
357 查看
题目:
Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
思路:
题目说的是不管新长度之后的内容,即前面留下的是无指定值的数
Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
思路:
题目说的是不管新长度之后的内容,即前面留下的是无指定值的数
public class Solution { public int removeElement(int[] A, int elem) { int size = A.length, index = 0; for(int i=0; i<size; i++){ if(A[i] != elem){ A[index++] = A[i]; } } return index; } }
相关文章推荐
- leetcode.array--27. Remove Element
- Leetcode 27. Remove Element
- leetcode--27. Remove Element
- Leetcode 27 Remove Element
- [leetcode 27] Remove Element
- LeetCode-27-Remove Element(消除数组中给定的元素)
- LeetCode 27 Remove Element
- LeetCode(27)Remove Element
- LeetCode 27_Remove Element
- Leetcode 27. Remove Element
- LeetCode 27 — Remove Element(C++ Java Python)
- [LeetCode]27 Remove Element
- [Leetcode]_27 Remove Element
- 27 | LeetCode | Remove Element
- leetcode-27 Remove Element
- leetcode 27. Remove Element
- LeetCode --- 27. Remove Element
- leetcode-27 Remove Element
- LeetCode(27)Remove Element
- leetcode 27:Remove Element