Find the second largest element in a Binary Search Tree
2015-02-18 06:36
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find the right most element. If this is a right node with no children, return its parent. if this
is not, return the largest element of its left child.
http://www.glassdoor.com/Interview/Find-the-second-largest-element-in-a-Binary-Search-Tree-QTN_238511.htm
Node
findSceondLargest(Node root) {
// If tree is null or is single node only, return null (no second largest)
if (root==null || (root.left==null && root.right==null)) return null;
Node parent = null, child = root;
// find the right most child
while (child.right!=null) {
parent = child;
child = child.right;
}
// if the right most child has no left child, then it's parent is second largest
if (child.left==null) return parent;
// otherwise, return left child's rightmost child as second largest
child = child.left;
while (child.right!=null) child = child.right;
return child;
}
is not, return the largest element of its left child.
http://www.glassdoor.com/Interview/Find-the-second-largest-element-in-a-Binary-Search-Tree-QTN_238511.htm
Node
findSceondLargest(Node root) {
// If tree is null or is single node only, return null (no second largest)
if (root==null || (root.left==null && root.right==null)) return null;
Node parent = null, child = root;
// find the right most child
while (child.right!=null) {
parent = child;
child = child.right;
}
// if the right most child has no left child, then it's parent is second largest
if (child.left==null) return parent;
// otherwise, return left child's rightmost child as second largest
child = child.left;
while (child.right!=null) child = child.right;
return child;
}
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