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List或者arraylist去掉重复数据(对象也可以)

2015-02-10 11:26 447 查看
法:将list或者arraylist中的数据加载到linkedhashset中 然后在加载到list或者arraylist中

测试用例如下:

[java]
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public class TestSet {

public static void main(String[] args) {
List<Student> list1 = new ArrayList<Student>();
list1.add(new Student("张三","12"));
list1.add(new Student("张三","12"));
list1.add(new Student("李四","12"));
list1.add(new Student("王五","15"));
list1.add(new Student("张三","12"));
list1.add(new Student("张三","13"));
System.out.println(list1.toString());
Set<Student> set = new LinkedHashSet<Student>();
set.addAll(list1);
List<Student> list2 = new ArrayList<Student>();
list2.addAll(set);
System.out.println(list2.toString());
}

}

对象:

[java]
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public class Student {

String name;
String age;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getAge() {
return age;
}
public void setAge(String age) {
this.age = age;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((age == null) ? 0 : age.hashCode());
result = prime * result + ((name == null) ? 0 : name.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Student other = (Student) obj;
if (age == null) {
if (other.age != null)
return false;
} else if (!age.equals(other.age))
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
return true;
}
@Override
public String toString() {
return "Student [name=" + name + ", age=" + age + "]";
}
public Student(String name, String age) {
super();
this.name = name;
this.age = age;
}
public Student() {
// TODO Auto-generated constructor stub
}
}
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