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leetcode[81]Search in Rotated Sorted Array II

2015-02-09 14:13 399 查看
Follow up for "Search in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Write a function to determine if a given target is in the array.

class Solution {
public:
bool search(int A[], int n, int target) {
if(A==NULL||n==0)return false;
int left=0, right=n-1;
int mid;
while(left<=right)
{
mid=(left+right)/2;
if(A[mid]==target)return true;
if (A[mid]==A[left]&&A[mid]==A[right])
{
left++;
right--;
}
else if(A[mid]>=A[left])
{
if(A[mid]<target)left=mid+1;
else
{
if(target>=A[left])right=mid-1;
else left=mid+1;
}
}
else
{
if(target<A[mid])right=mid-1;
else
{
if (target<=A[right])left=mid+1;
else right=mid-1;
}
}
}
return false;
}
};
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