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BZOJ2429: [HAOI2006]聪明的猴子

2015-01-28 13:27 155 查看
题目:http://www.lydsy.com/JudgeOnline/problem.php?id=2429

题解:从某一点遍历n个点,且使最长边最短,就是MST了。

代码:

#include<cstdio>

#include<cstdlib>

#include<cmath>

#include<cstring>

#include<algorithm>

#include<iostream>

#include<vector>

#include<map>

#include<set>

#include<queue>

#include<string>

#define inf 1000000000

#define maxn 1000+5

#define maxm 200000+5

#define eps 1e-10

#define ll long long

#define pa pair<int,int>

#define for0(i,n) for(int i=0;i<=(n);i++)

#define for1(i,n) for(int i=1;i<=(n);i++)

#define for2(i,x,y) for(int i=(x);i<=(y);i++)

#define for3(i,x,y) for(int i=(x);i>=(y);i--)

#define for4(i,x) for(int i=head[x],y=e[i].go;i;i=e[i].next,y=e[i].go)

#define for5(n,m) for(int i=1;i<=n;i++)for(int j=1;j<=m;j++)

#define mod 1000000007
#define sqr(x) (x)*(x)

using namespace std;

inline int read()

{

int x=0,f=1;char ch=getchar();

while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}

while(ch>='0'&&ch<='9'){x=10*x+ch-'0';ch=getchar();}

return x*f;

}
int n,m;
double mx,b[maxn],d[maxn];
bool v[maxn];
struct rec{int x,y;}a[maxn];
priority_queue<pa,vector<pa>,greater<pa> >q;
inline double dist(int x,int y){return sqrt(sqr(a[x].x-a[y].x)+sqr(a[x].y-a[y].y));}
inline void prim()
{
for1(i,n)d[i]=inf;
d[1]=0;
q.push(pa(0,1));
while(!q.empty())
{
int x=q.top().second;q.pop();
if(v[x])continue;v[x]=1;
if(d[x]>mx)mx=d[x];
for1(i,n)if(!v[i]&&dist(i,x)<d[i])
{
d[i]=dist(i,x);
q.push(pa(d[i],i));
}
}
}

int main()

{

freopen("input.txt","r",stdin);

freopen("output.txt","w",stdout);

m=read();
for1(i,m)b[i]=read();
n=read();
for1(i,n)a[i].x=read(),a[i].y=read();
prim();
int ans=0;
for1(i,m)if(b[i]>=mx)ans++;
cout<<ans<<endl;

return 0;

}


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