3.Longest Substring Without Repeating Characters Leetcode Python
2015-01-27 05:11
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Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest substring is "b", with the length
of 1.
第一种方法是利用左指针和右指针选出substring 然后判断substring里面是否有重复,如果没有重复右指针向右继续前进,否则左指针前进。
在这个过程中maintain maxlen=max(maxlen,len(substring))
代码如下,这个算法时间是n^2 但是过不了最后的一个长的case:
class Solution:
# @return an integer
def unique(self,str):
d={}
for elem in str:
if elem not in d:
d[elem]=1
else:
return False
return True
def lengthOfLongestSubstring(self, s):
left=0
right=0
maxlen=0
while right<=len(s):
substr=s[left:right]
if self.unique(substr):
maxlen=max(maxlen,len(substr))
right+=1
else:
left+=1
return maxlen
第二种算法对第一中算法进行优化
class Solution:
# @return an integer
def lengthOfLongestSubstring(self, s):
if len(s)<=1:
return len(s)
left=0
right=0
maxlen=0
substr=''
for right in range(len(s)):
if s[right] not in substr:
substr=substr+s[right]
else:
maxlen=max(maxlen,len(substr))
while s[left]!=s[right]:
left+=1
left+=1
substr=s[left:right+1]
return max(maxlen,len(substr))
of 1.
第一种方法是利用左指针和右指针选出substring 然后判断substring里面是否有重复,如果没有重复右指针向右继续前进,否则左指针前进。
在这个过程中maintain maxlen=max(maxlen,len(substring))
代码如下,这个算法时间是n^2 但是过不了最后的一个长的case:
class Solution:
# @return an integer
def unique(self,str):
d={}
for elem in str:
if elem not in d:
d[elem]=1
else:
return False
return True
def lengthOfLongestSubstring(self, s):
left=0
right=0
maxlen=0
while right<=len(s):
substr=s[left:right]
if self.unique(substr):
maxlen=max(maxlen,len(substr))
right+=1
else:
left+=1
return maxlen
第二种算法对第一中算法进行优化
class Solution:
# @return an integer
def lengthOfLongestSubstring(self, s):
if len(s)<=1:
return len(s)
left=0
right=0
maxlen=0
substr=''
for right in range(len(s)):
if s[right] not in substr:
substr=substr+s[right]
else:
maxlen=max(maxlen,len(substr))
while s[left]!=s[right]:
left+=1
left+=1
substr=s[left:right+1]
return max(maxlen,len(substr))
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