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Python 实现简单的密码判断

2015-01-19 09:57 309 查看
passwdList = ("nihao", "nihao1", "nihao2")

valid = False
count = 3
while count > 0:
input = raw_input("enter password: ")
# check for valid passwd
for eachPasswd in passwdList:
if input == eachPasswd:
valid = True
break
if not valid:
print "invalid input"
count -= 1
continue
else:
print 'Password check pass!'
break

if not valid:
print 'Password check Fail!'
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