javascript 返回数组中不重复的元素

http://www.jb51.net/article/21329.htm

返回数组中不重复的元素的js实现代码。

这是实现结构伪类type-of-type的部分代码：

<script type="text/javascript">

var ret= ["span","span","strong","span","b"]

var norepeat = function(array){

var set = array.join(",")+",";

while(array.length){

var el = array.shift();

set = set.replace(el+",","");

if(set.indexOf(el+",") != -1){

set = set.replace(new RegExp(el+",","g"),"");

array = set.replace(/,$/g,"").split(",");

}else{

set = el+","+set;

}

}

return set.replace(/,$/g,"").split(",")

}

alert(norepeat(ret))//最后返回b,strong

</script>

觉得效果不高，向无忧高手求救。下面是客服果果的(好强大的正则替换啊)：

<script language="javascript">

var ret= ["span","span","strong","span","b"];

var norepeat=function (x) {

var y='c0cb5f0fcf239ab3d9c1fcd31fff1efc';

return x.sort().join(y).replace(RegExp('(.*('+y+'|$))\\1+','g'),'').split(y);

};

alert(norepeat(ret));

</script>

abcdreamer 的实现（此实现能过滤非纯字符串数组里的重复，我比较喜欢）：

<script language="javascript">

var a = ["span","span","strong","span","b"];

function norepeat(a) {

var i = a.length, j, b;

while (i--) {

j = i;

b = false;

while (j--) {

if (a[i] === a[j]) {

a.splice(j, 1);

i--;

b = true;

}

}

if (b) a.splice(i, 1);

}

return a;

}

alert(norepeat(a));

</script>

哪位高手有更好的实现，请告诉我一声！

看来有些人不明白norepeat函数与unique函数的区别，norepeat是去除数组中重复的元素，如果数组中有两个a，则去除这两个，unique则会去除其中之一。下面是unique函数的实现：

<script language="javascript">

Array.prototype.inArray = function(el){

for (var i=0,n=this.length;i<n;i++ )

if(this[i]===el)return true;

return false;

}

Array.prototype.unique = function() {

var i = 0, n = this.length,ret = [];

for (; i < n; i++)

if (!ret.inArray(this[i])) ret.push(this[i]);

return ret;

};

var ret= ["span","span","strong","span","b"]

alert(ret.unique()) //返回"span","strong","b"

</script>