用Android搭建客户端 手机和服务器…

首先在服务器端，采用的是SSH框架，struts
2集合了JSON插件，服务器和客户端的信息交互采用的JSON来传输，由于在服务器端用了Struts
2，所以我就用装了一个JSON插件。这样，很轻易的就把服务器端的信息用JSON的形式发送到了手机端。以下是代码：

首先，在服务器端搭建好SSH框架，具体细节就不在陈述。struts.xml配置如下：

<packagename="login"extends="json-default">

<actionname="login"class="com.jclick.test.LoginAction"method="login">

<resulttype="json"><paramname="includeProperties">result</param></result>

</action>

</package>

<packagename="login"extends="json-default">

<actionname="login"class="com.jclick.test.LoginAction"method="login">

<resulttype="json"><paramname="includeProperties">result</param></result>

</action>

</package>

手机端的代码如下：

首先，手机端有一个缓存类，主要用于缓存一些手机端需要访问的数据，这样的好处是可以达达节省手机和服务器的交互，用单例实现的：

package com.lyc;

public class Cache {

private User User;

public
Cache(){

}

private static class CacheHolder{

private static final Cache
INSTANCE=new Cache();

}

public static Cache getInstance(){

return
CacheHolder.INSTANCE;

}

public User getUser(){

return User;

}

public void setUser(User User){

this.User=User;

}

}

接着开始书写手机端的协议，用户向服务器发送请求，同时服务器反馈给手机端信息的：

package com.lyc;

import java.io.BufferedReader;

import java.io.InputStreamReader;

import java.util.ArrayList;

import java.util.List;

import org.apache.http.HttpResponse;

import org.apache.http.NameValuePair;

import org.apache.http.client.entity.UrlEncodedFormEntity;

import org.apache.http.client.methods.HttpPost;

import org.apache.http.impl.client.DefaultHttpClient;

import org.apache.http.message.BasicNameValuePair;

import org.json.JSONException;

import org.json.JSONObject;

public class BaseProtocol {

private StringBuilder sb=new
StringBuilder();

private
org.apache.http.client.HttpClient
httpClient;

private HttpPost httpRequest;

private HttpResponse
response;

private
List<NameValuePair> nameValuePair =
new ArrayList<NameValuePair>();

BaseProtocol(){ httpClient =
new DefaultHttpClient();

}

protected void pack(String url) throws
Exception{

httpClient =new
DefaultHttpClient();

httpRequest = new
HttpPost(url);

httpRequest.setEntity(new
UrlEncodedFormEntity(nameValuePair));

response=httpClient.execute(httpRequest);

}

protected void parse() throws Exception{

//TODO状态处理500200

if(response.getStatusLine().getStatusCode()==200){

BufferedReader
bufferedReader2=new BufferedReader(

new
InputStreamReader(response.getEntity().getContent()));

for(String
s=bufferedReader2.readLine(); s!=null;
s=bufferedReader2 .readLine()){

sb.append(s);

}

}

}

public void addNameValuePair(String key,String
value){

nameValuePair.add(new
BasicNameValuePair(key,value));

}

public JSONObject getJSON() throws
JSONException{

return new
JSONObject(sb.toString());

}

}

接着是登录协议，在这里我只是模拟登陆使用的一个类，仅供大家参考：

importorg.json.JSONObject;

importcom.jclick.bean.User;

publicclassLoginProtocolextendsBaseProtocol{

privatefinalstaticStringURL="http://localhost:8080/test/login";

publicbooleancheckLogin(Userusr){

try{

pack(URL);

parse();

JSONObjectobj=this.getJSON();

if(obj.getString("result").equals("failed")){

returnfalse;

}else{

returntrue;

}

}catch(Exceptione){

e.printStackTrace();

returnfalse;

}

}

}

然后是User实体类，主要用于保存用户信息：

publicclassUser{

privateStringusername;

privateStringpassword;

publicStringgetUsername(){

returnusername;

}

publicvoidsetUsername(Stringusername){

this.username=username;

}

publicStringgetPassword(){

returnpassword;

}

publicvoidsetPassword(Stringpassword){

this.password=password;

}

}

最后就是LoginActivity里边判断登陆的代码了，详细代码不再贴出来了，仅贴一个判断登陆的代码：

privatevoidcheckedData(){

username=((EditText)findViewById(R.id.username)).getText().toString();

password=((EditText)findViewById(R.id.password)).getText().toString();

Useruser=newUser();

user.setUsername(username);

user.setPassword(password);

LoginProtocollogin=newLoginProtocol();

booleanresult=login.checkLogin(user);

if(result){SpiderCache.getInstance().setUserSession(user);

Toast.makeText(getApplicationContext(),"登录成功",1000).show();

Intentintent=newIntent();

intent.setClass(LoginActivity.this,WelcomeActivity.class);

startActivity(intent);

}else{Toast.makeText(LoginActivity.this,"密码或用户名不匹配，请重新输入！",1000).show();

}

}