函数的返回竟然能作为左值

#include <iostream>
#include <iomanip>
#include <stdio.h>
using namespace std;

struct CAssoc
{
CAssoc* pNext;
void* unused;
void* value;
};
CAssoc *gpGloable=NULL;

void*& func(CAssoc **temp);

void main()
{
func(&gpGloable)="ABCDEFGHIJKLMNOPQRST";

cout<<(char*)gpGloable->value<<endl;
printf("%s\n\n",gpGloable->value);

//
//////////////////////////////////////////////////////////////////////////
unsigned int a=100;
unsigned int *p=NULL;
p=&a;
unsigned int **q=NULL;
q=&p;
cout<<a<<"\t"<<*p<<"\t"<<p<<"\t"<<**(&p)<<endl;
printf("%d\n\n",*p);

//
//////////////////////////////////////////////////////////////////////////
CAssoc ss;
ss.unused=&a;
ss.value="FFFFFFFF";
unsigned int xx=(unsigned int)(*&(ss.unused));
cout<<hex<<setw(8)<<xx<<endl;
cout<<(int*)(ss.unused)<<endl;
printf("%d\n\n",*&(ss.unused));
printf("rrrrrrr%d\n\n",((int*)(ss.unused)));
cout<<(char*)ss.value<<endl;
printf("%s\n\n",ss.value);
}

void*& func(CAssoc **temp)
{
CAssoc *p=new CAssoc;
*temp=p;
return p->value;
}