您的位置:首页 > 其它

[leetcode 133]Clone Graph

2014-12-28 17:04 295 查看
Clone an undirected graph. Each node in the graph contains a
label
and a list of its
neighbors
.

OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use
#
as a separator for each node, and
,
as
a separator for node label and each neighbor of the node.

As an example, consider the serialized graph
{0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by
#
.

First node is labeled as
0
. Connect node
0
to
both nodes
1
and
2
.
Second node is labeled as
1
. Connect node
1
to
node
2
.
Third node is labeled as
2
. Connect node
2
to
node
2
(itself), thus forming a self-cycle.

Visually, the graph looks like the following:
1
/ \
/   \
0 --- 2
/ \
\_/


/**
* Definition for undirected graph.
* struct UndirectedGraphNode {
*     int label;
*     vector<UndirectedGraphNode *> neighbors;
*     UndirectedGraphNode(int x) : label(x) {};
* };
*/
class Solution {
public:
UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) {
if (node == NULL) {
return NULL;
}
map<int, UndirectedGraphNode *> nodes;
queue<UndirectedGraphNode*> q;
q.push(node);
while (!q.empty()) {
UndirectedGraphNode *tmp = q.front();
q.pop();
if (nodes.find(tmp->label) == nodes.end()) {
UndirectedGraphNode *newNode = new UndirectedGraphNode(tmp->label);
nodes.insert(pair<int,UndirectedGraphNode*>(tmp->label,newNode));
for (auto i = 0; i < tmp->neighbors.size(); i++) {
q.push(tmp->neighbors[i]);
}
}
}
q.push(node);
while(!q.empty()) {
UndirectedGraphNode* tmp = q.front();
q.pop();
UndirectedGraphNode* tmp2 = nodes[tmp->label];
if  (tmp2->neighbors.empty() && !tmp->neighbors.empty()) {
for (auto i = 0; i < tmp->neighbors.size(); i ++) {
tmp2->neighbors.push_back(nodes[tmp->neighbors[i]->label]);
q.push(tmp->neighbors[i]);
}
}
}
return nodes[node->label];

}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: