【LeetCode】Remove Duplicates from Sorted List
2014-12-09 00:08
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题意:
Given a sorted linked list, delete all duplicates such that each element appear only once.For example,
Given
1->1->2, return
1->2.
Given
1->1->2->3->3, return
1->2->3.
思路:
删除链表中的重复项,考察链表操作。主要是用循环判断当前节点和下一级节点的值是否相同,是则修改当前节点的 next 指针指向下一节点的 next。
注意操作时要判断指针非空。
代码:
C++:/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *deleteDuplicates(ListNode *head){ /*保存头指针*/ ListNode* root = head; while(head != NULL) { /*下一节点存在,且当前节点和下一节点的值重复*/ while(head->next != NULL && head->val == head->next->val) { head->next = head->next->next; } head = head->next; } return root; } };Python:
# Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: # @param head, a ListNode # @return a ListNode def deleteDuplicates(self, head): p = head while p != None: while p.next != None and p.val == p.next.val: p.next = p.next.next p = p.next return head
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